2log(base 5)^(x-3)-log(base 5)^8= log(base 5)^2

Mathematics

1 answer:

Alja [10]3 years ago

7 0

Answer:

x = 7

Step-by-step explanation:

$2log_5(x-3)-log_58= log_52\\\\2log_5(x-3) =log_52+log_58\\\\2log_5(x-3) =log_5(2\times 8) \\\\2log_5(x-3) =log_516\\\\2log_5(x-3) =log_54^2 \\\\2log_5(x-3) =2 log_54 \\\\log_5(x-3) =log_54 \\\\x - 3 = 4\\\\x = 4+3\\\\\huge \orange { \boxed{x = 7}}$

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