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3 years ago

15 points Which graph represents the function g(x) = |x+4|+2?

Mathematics

2 answers:

rewona [7]3 years ago

7 0

Answer:

number 3

Step-by-step explanation:

nikklg [1K]3 years ago

7 0

It is c correct me if I’m wrong

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Select the correct answer from each drop-down menu. Identify the investment type and complete the description. _____offer corpor

ladessa [460]

Answer: bonds/safety/income based on an interest rate 

Step-by-step explanation:

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3 years ago

I am a 3 digit number. I have the largest 1 digit number in the tens place , the number that has the same place value always in

sineoko [7]

Answer: 490

Step-by-step explanation:

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3 years ago

If angle 2 is 74 degrees, what is angle 7?

mojhsa [17]

Answer:

106

Step-by-step explanation:

Depending on the angle it has to equal 180

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4 years ago

The number 49 has exactly three factors. Since 98 is a multiple of 49, which must be true of 98? It must have only two factors.

Mumz [18]

Answer:

Step-by-step explanation:

⇒49=7×7 =1 × 49

Factors of 49 = 1,7,49

⇒It is given that ,98 is a Multiple of 49.

98 = 49 × 2

So, apart from factors of 49, number 2, and 98 are also included in the set of factors of 98.

→Factors of 98 are =1,2,7,49,98

3 0

3 years ago

If you are dealt five cards from a shuffled deck of 52 cards find the probability of getting three queens and two kings

dexar [7]

The probability of getting three queens and two kings is $\frac{1}{1082900}$

Solution:

Given that , you are dealt five cards from a shuffled deck of 52 cards

We have to find the probability of getting three queens and two kings

Now, we know that, in a deck of 52 cards, we will have 4 queens and 4 kings.

$\text { probability of an event }=\frac{\text { favarable possibilities }}{\text { number of possibilities }}$

Probability of first queen:

$\text { Probability for } 1^{\text {st }} \text { queen }=\frac{4}{52}=\frac{1}{13}$

Probability of second queen:

$\text { Plobability for } 2^{\text {nd }} \text { queen }=\frac{3}{51}=\frac{1}{17}$

Here we used 3 for favourable outcome, since we already drew 1 queen out of 4

And now number of outcomes = 52 – 1 = 51

Probability of third queen:

Similarly here favorable outcome = 2, since we already drew 2 queen out of 4

And now number of outcomes = 51 – 1 = 50

$\text { Probability of } 3^{\text {rd }} \text { queen }=\frac{2}{50}=\frac{1}{25}$

Probability for first king:

Here kings are 4, but overall cards are 49 as 3 queens are drawn

$\text { probability for } 1^{\text {st }} \text { king }=\frac{4}{49}$

Probability for second king:

Here, kings are 3 and overall cards are 48 as 3 queens and 1 king are drawn

$\text { probability of } 2^{\text {nd }} \text { king }=\frac{3}{48}=\frac{1}{16}$

And, finally the overall probability to get 3 queens and 2 kings is:

$=\frac{1}{13} \times \frac{1}{17} \times \frac{1}{25} \times \frac{4}{49} \times \frac{1}{16}=\frac{4}{4331600}=\frac{1}{1082900}$

Hence, the probability is $\frac{1}{1082900}$

7 0

3 years ago