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add 0+1+2+3+4 = 10
divide 10÷5 = 2
add 15+8+3+3+1 = 30
divide 30÷5 = 6
the ratio is 2:6 which simplifies to 1:3 by the means of lates per student. In other words there is one late per 3 students.
In the diagram, ∠2 and ∠6 are the same as well as ∠4 and ∠8. If we added ∠2 and ∠6, they would equal 180°...therefore, if we subtract 106 from 180, we are left with 74° for the answer to ∠8
Answer:
If you draw this out, you can see that total fence equation will be:
2L + 4W = 1200
Simplify, divide by 2
L + 2W = 600
L = (600-2W)
:
Area;
A = L*W
Substitute (600-2W) for L:
A = (600-2W)*W
A = -2W^2 + 600W; a quadratic equation
:
The dimension that will produce the greatest area will be the "axis of symmetry
which is: x = %28-b%29%2F%282a%29
:
In this equation a=-2, b=600
W = %28-600%29%2F%282%2A-2%29
W = %28-600%29%2F%28-4%29
W = +150 ft is the width
:
Find the length
L = 600 - 2(150)
L = 300 ft is the length
:
We can say the a field 300 by 150 gives he greatest area
:
This illustrated on a graph where y axis is the area and x axis is the width:
Step-by-step explanation:
