Answer:
. 2 m/s
Step-by-step explanation:
Speed is defined as the rate of change in distance per time.
in this case you can simply observe the graph to get the final and initial distances & time.
The motion starts from 0 and moves to 2 if you look at the y axis of the graph.
Thus, the initial distance is 0m & the final distance is 2m
The time is specified in the question to have an initial of 0 sec and a final of 1 sec.
now let's plot our values out as a given.
S1 = 0m t1 = 0 sec
S2 = 2m t2 = 1 sec
and so you're going to have to find the change in time and displacement individually to later engage both in your formula which is - ∆V = ∆S / ∆t
∆S = S2 - S1 = 2m - 0m = 2m.
∆t = t2 - t1 = 1 sec - 0 sec = 1 sec.
∆V = ∆S / ∆t = 2m / 1 sec = 2m/sec (2m/s)
Answer:
18.75=p
s=14.06
b=2.34
Step-by-step explanation:
37.75=b+s+p
-4
33.75=b+s+p
s=3/4p
b=1/6s
33.75=1/6(3/4p)+3/4p+p
33.75=3/20p+3/4p+p
(33.75=18/20p+p)20
675=18p+p)/18
37.50=2p)/2
18.75=p
s=3/4p
3/4(18.75)
s=14.06
b=1/6s
1/6(14.06)
b=2.34
37.75-4=18.75+14.06+2.34=35.15
im missing 50 cents somewhere its wrong but close i think sorry
If we divide 56 by 4 we get 14. Why by4? So that one number is 3 times the other So he had 14 balls that went into the green bags and 42 (56-14) that went into the red bags. We could just answer the question and say 14 but I think they want to know how many in each green bag.
14 and 42 don't work because they are not the same number of balls. What number is a common factor? 7 is,
We could have 2 green bags and split the 14 balls into 2 groups of 7 and with the remaining 42 - put them into 6 red bags of 7 each.
And so the answer to your question is:
7 ball in each bag = 2 bags are green, and 6 bags are red
14 balls + 42 balls = 56 bouncy balls
The answer to your question should be EF
Yes they are both equivalents because they are whole's and some examples would be 8/8,9/9,4/4. and 5/5 because they are all whole's 7 out of 7 pieces of pizza is the whole pizza.
