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AlexFokin [52]
3 years ago
12

You work at Dave's Donut Shop. Dave has asked you to determine how much each box of a dozen donuts should cost. There are 12 don

uts in one dozen. You determine that it costs $0.27 to make each donut. Each box costs $0.16 per square foot of cardboard. There are 144 square inches in 1 square foot. Whats an expression to model the number of donuts in b boxes?
Mathematics
1 answer:
Archy [21]3 years ago
3 0

Answer:

Donuts(b) = 12*b

Step-by-step explanation:

Notice that the question is:

What's an expression to model the number of donuts in b boxes?

We know that we are talking of boxes of a dozen donuts.

We know that in one dozen, we have 12 donuts.

Then if we have b boxes, and in each box we have 12 donuts, we will have a total of b times 12 donuts, the expression is:

Donuts(b) = 12*b

There is a lot of information here that we did not use (like the cost of cardboard and donuts), and that may be there just to distract us, the important thing to do here is:

See what is the thing we want to find (in this case, the number of donuts in b boxes)

Find the relevant information to solve this. (ignore the irrelevant information)

Solve the question.

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Please teach me on how to answer this question. (addmath question)
arsen [322]

We know that \overline{x}=8 so:

\overline{x}=8\\\\\\\dfrac{\sum\limits_{k=1}^7\,x_k}{7}=8\qquad|\cdot7\\\\\\ \boxed{\sum\limits_{k=1}^7\,x_k=56}

We want to calculate:

\sum\limits_{k=1}^7\,\big(2x_k-3\big)^2=\sum\limits_{k=1}^7\,\big(4x_k^2-12x_k+9\big)=\\\\\\=\sum\limits_{k=1}^7\,4x_k^2-\sum\limits_{k=1}^7\,\big12x_k+\sum\limits_{k=1}^7\,9=4\sum\limits_{k=1}^7\,x_k^2-12\sum\limits_{k=1}^7\,x_k+\sum\limits_{k=1}^7\,9=\\\\\\=4\cdot672-12\cdot56+7\cdot9=2688-672+63=\boxed{2079}

5 0
2 years ago
Which term describes the red curve in the figure below?
Scorpion4ik [409]

Answer:

Hyperbola

Step-by-step explanation:

Its just like a parabola, but with 2 equal cones making them on opposite sides.

3 0
1 year ago
Read 2 more answers
Find the 9th term of the geometric sequence whose common ratio is 1/3 and whose first term is 2.
raketka [301]

Answer:

2/6561

Step-by-step explanation:

Geometric sequence formula : a_n=a_1(r)^n^-^1

where an = nth term, a1 = first term , r = common ratio and n = term position

given ratio : 1/3 , first term : 2 , given this we want to find the 9th term

to do so we simply plug in what we are given into the formula

recall formula : a_n=a_1(r)^n^-^1

define variables : a1 = 2 , r = 1/3 , n = 9

plug in values

a9 = 2(1/3)^(9-1)

subtract exponents

a9 = 2(1/3)^8

evaluate exponent

a9 = 2 (1/6561)

multiply 2 and 1/6561

a9 = 2/6561

7 0
2 years ago
If p(x)=x^2+x+1 and q(x)=3x^2-1, find p(7)
Delvig [45]

Answer:

p(7) = 57

Step-by-step explanation:

Because this is a function, all you have to do is input 7 for x like so:

p(x)=x^2+x+1 --------------->     p(7)=7^2+7+1

                                            so 49 + 8

                                                = 57

7 0
2 years ago
Distance between parallel lines y=3x+10 and y=3x-20
Alecsey [184]

1. Take an arbitrary point that lies on the first line y=3x+10. Let x=0, then y=10 and point has coordinates (0,10).


2. Use formula d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+B^2}} to find the distance from point (x_0,y_0) to the line Ax+By+C=0.


The second line has equation y=3x-20, that is 3x-y-20=0. By the previous formula the distance from the point (0,10) to the line 3x-y-20=0 is:

d=\dfrac{|3\cdot 0-10-20|}{\sqrt{3^2+(-1)^2}}=\dfrac{30}{\sqrt{10}}=3\sqrt{10}.


3. Since lines y=3x+10 and y=3x-20 are parallel, then the distance between these lines are the same as the distance from an arbitrary point from the first line to the second line.


Answer: d=3\sqrt{10}.

4 0
2 years ago
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