Question

One number is five more than twice another. If their sum is decreased by ten, the result is twenty-two. Find the numbers.

Answer 1

(x+2x+5)-10=22
3x+5=32
3x=27
x=9
So, the numbers are 3 and 11

Answer 2

X = 2y + 5
(x + 2y + 5) - 10 = 22
(2y + 5 + 2y + 5) = 4y + 10
(4y + 10) - 10 = 22
4y = 22   y = 5.5
x = 2(5.5) + 5  x = 16
x = 16  y = 5.5