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3 years ago

One number is five more than twice another. If their sum is decreased by ten, the result is twenty-two. Find the numbers.

Mathematics

2 answers:

Angelina_Jolie [31]3 years ago

8 0

(x+2x+5)-10=22
3x+5=32
3x=27
x=9
So, the numbers are 3 and 11

saveliy_v [14]3 years ago

4 0

X = 2y + 5
(x + 2y + 5) - 10 = 22
(2y + 5 + 2y + 5) = 4y + 10
(4y + 10) - 10 = 22
4y = 22 y = 5.5
x = 2(5.5) + 5 x = 16
x = 16 y = 5.5

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20 Answer: a₁ = 4

Step-by-step explanation:

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21 Answer: n = 13

Step-by-step explanation:

$a_n=\dfrac{1}{64},\ a_1=64,\ r=\dfrac{1}{2}\\\\a_n=a_1 \cdot r^{n-1}\\\\\dfrac{1}{64}=64\cdot \bigg(\dfrac{1}{2}\bigg)^{n-1}\\\\\dfrac{1}{64\cdot 64}=\bigg(\dfrac{1}{2}\bigg)^{n-1}\\\\\dfrac{1}{2^6\cdot 2^6}=\dfrac{1}{2^{n-1}}\\\\6+6=n-1\\\\\large\boxed{13}=n$

22 Answer: n = 5

Step-by-step explanation:

$a_n=48,\ a_1=1875\ r=\dfrac{2}{5}\\\\a_n=a_1 \cdot r^{n-1}\\\\48=1875\cdot \bigg(\dfrac{2}{5}\bigg)^{n-1}\\\\\dfrac{48}{1875}=\bigg(\dfrac{2}{5}\bigg)^{n-1}\\\\\dfrac{16}{625}=\bigg(\dfrac{2}{5}\bigg)^{n-1}}\\\\\bigg(\dfrac{2}{5}\bigg)^4=\bigg(\dfrac{2}{5}\bigg)^{n-1}}\\\\4=n-1\\\\\large\boxed{5}=n$

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Read 2 more answers

−

irakobra [83]

Answer: =296

Step-by-step explanation: −2*4=-8+20=28*3=84+48=132*2=164−2=162*4+20*3+48*2= 296

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Answer:

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Step-by-step explanation:

you have to use the sine rule = side you know * ( sin of angle opposing the side you want to know / sin of angle opposing the side you know)

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Step-by-step explanation:

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