-1.1-1.9, 1.9,1.1,2.1,-3.9,3.-9,-2.-1
Answer:
Three days at the most.
Step-by-step explanation:
First you must see how much money he spends on driving, 75 x 0.10 = 7.5. Subtract that from 120 to get 112.5. He has that much money left. Now you will divide 112.5 by 30.05. 112.5/30.05 = 3.74376039933. Simplify to get 3.
(also, he will have 22.35 dollars left)
Answer:
3 I think not sure.........
The data given as a whole would be called ungrouped data. Now to get the variance, you will need the formula:
s^2= <u>Σ(x-mean)^2</u>
n
x = raw data
mean = average of all data
n = no. of observations
s^2 = variance
Now we do not have the mean yet, so you have to solve for it. All you need to do is add up all the data and divide it by the number of observations.
Data: <span>90, 75, 72, 88, 85 n= 5
</span>Mean=<u>Σx</u>
n
Mean = <u>90+75+72+88+85 </u> = <u>410</u> = 82
5 5
The mean is 82. Now we can make a table using this.
The firs column will be your raw data or x, the second column will be your mean and the third will be the difference between the raw data and the mean and the fourth column will be the difference raised to two.
90-82 = 8
8^2 =64
75-82 = -7
-7^2 =49
72-82 = -10
-10^2=100
88-82=6
6^2 = 12
85-82=3
3^2=9
Now you have your results, you can now tabulate the data:
x mean x-mean (x-mean)^2
90 82 8 64
75 82 -7 49
72 82 -10 100
88 82 6 36
85 82 3 9
Now that you have a table, you will need the sum of (x-mean)^2 because the sigma sign Σ in statistics, means "the sum of."
64+49+100+36+9 = 258
This will be the answer to your question. The value of the numerator of the calculation will be 258.
<u>
</u>
Answer:
<h2>The distance to the Eath's Horizon from point P is 352.8 mi, approximately.</h2>
Step-by-step explanation:
You observe the problem from a graphical perspective with the image attached.
Notice that side 
is tangent to the circle, which means is perpendicular to the radius which is equal to 3,959 mi.
We have a right triangle, that means we need to use the Pythagorean's Theorem, to find the distance to the Earth's Horizon from point P.
The hypothenuse is 3959 + 15.6 = 3974.6 mi.
Therefore, the distance to the Eath's Horizon from point P is 352.8 mi, approximately.
