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3 years ago

Explain how to use a polynomial identity to factor x^6-27y^3

Mathematics

2 answers:

Umnica [9.8K]3 years ago

6 0

Dont really no sorry

Taya2010 [7]3 years ago

5 0

This is a sum of cubes:

x⁶ - 27y³ = (x²)³ + (-3y)³

Recall that

a³ + b³ = (a + b) (a² - ab + b²)

So we have

x⁶ - 27y³ = (x² - 3y) ((x²)² - x² (-3y) + (-3y)²)

x⁶ - 27y³ = (x² - 3y) (x⁴ + 3x²y + 9y²)

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Shay mal e 8 2/3 cups of snacks mix she puts all the snack mix into plastic bags she puts 1/3 cup of the snack mix in each bag h

AnnyKZ [126]

Answer:

She needs 26 plastic bags.

Step-by-step explanation:

Given:

Amount of cups of snacks mix = 8 2/3

Rewriting 8 2/3 we get,

Amount of snacks mix = $\frac{26}{3}$

Number of Cups in each bag = $\frac{1}{3}$

She puts all the snacks mix in plastic bags

We need to find the number of plastic bags required to put all the snacks mix

Let number of plastic bag be x.

hence we can say that Number of Cups in each bag multiplied by number of plastic bag is equal to Amount of snacks mix.

$\frac{1}{3}x=\frac{26}{3}\\\\x= \frac{26\times3}{3\times1} =26$

Hence total number of plastic bags she needs is 26.

6 0

3 years ago

PLEASE HELP ASAP TAKING TEST

diamong [38]

The first choice !!!

8 0

3 years ago

Read 2 more answers

Which of the following is the best graph of the point below

Svet_ta [14]

There’s no graph belowww

3 0

3 years ago

Round 123,949 to the underlined point. 4 is highlighted

ehidna [41]

$\\ \sf\longmapsto 123,949$

9 is greater than 5

$\\ \sf\longmapsto 123,95$

$\\ \sf\longmapsto 123,9$

9 is greater than 5

$\\ \sf\longmapsto 124$

4 is less than 5

$\\ \sf\longmapsto 12$

2 is less than 5

$\\ \sf\longmapsto 1$

Note

Write the number until underlined point.I did it till end

5 0

3 years ago

Read 2 more answers

#54 Simplify and write the answers using positive exponents only.

kramer

Gg easy

remember
(x^m)/(x^n)=x^(m-n)
and
(x^m)^n=x^(mn)
and
(xyz)^m=(x^m)(y^m)(z^m)
and
(m/n)^a=(m^a)/(n^a)
and
x^-n=1/(x^n)

so
$( \frac{6mn^{-2}}{3m^{-1}n^2} )^{-3}$ =
$( \frac{6}{3} )^{-3}( \frac{m}{m^{-1}} )^{-3}( \frac{n^{-2}}{n^2} )^{-3}$ =
$(2^{-3})((m^2)^{-3})((n^{-4})^{-3})$ =
$( \frac{1}{2^3})(m^{-6})(n^{12})$ =
$( \frac{1}{8} )( \frac{1}{m^6})(n^{12})$ =
$\frac{n^{12}}{8m^6}$

8 0

3 years ago