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andrew11 [14]
3 years ago
13

Look at the picture and answer what the time of day the earth is and what caused it to look like it.

Physics
2 answers:
katrin2010 [14]3 years ago
6 0

Answer:

The top picture is day and its bc the sun is facing that side of the Earth. The bottom pic is night time and that side of earth is not facing the sun :/

Explanation:

idunooo

oksano4ka [1.4K]3 years ago
4 0

First Square is Like 12:00pm The Next is Like 12:00am

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Draw the curve for determining the value of g using compound pendulum.
____ [38]

Given that,

Acceleration due to gravity = g

Time period :

Time period is defined as,

T = 2\pi\sqrt{\dfrac{l}{g}}

Where, l = length of pendulum

g = acceleration due to gravity

We need to calculate the value of g

Using formula of time period

T=2\pi\sqrt{\dfrac{l}{g}}

g=\dfrac{4\pi^2l}{T^2}

Where, T = time period

l = length of pendulum

Hence, The value of g is \dfrac{4\pi^2l}{T^2}

3 0
4 years ago
A 190 g air-track glider is attached to a spring. The glider is pushed in 9.20 cm and released. A student with a stopwatch finds
Sholpan [36]

Answer:

k = 12.136\,\frac{N}{m}

Explanation:

The angular frequency of the system is:

\omega = \sqrt{\frac{k}{m} }

The frequency is:

f = \frac{14\,osc}{11\,s}

f = 1.272\,hz

The angular frequency is:

\omega = 2\pi\cdot (1.272\,hz)

\omega = 7.992\,\frac{rad}{s}

The spring constant is:

k = \left(7.992\,\frac{rad}{s} \right)^{2}\cdot (0.190\,kg)

k = 12.136\,\frac{N}{m}

6 0
3 years ago
Occasionally, people can survive falling large distances if the surface they land on is soft enough. During a traverse of Eiger'
uranmaximum [27]

Answer:

4611.58 ft/s²

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 32.174 ft/s²

Equation of motion

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 32.174\times 516+0^2}\\\Rightarrow v=182.218\ ft/s

v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-182.218^2}{2\times 3.6}\\\Rightarrow a=-4611.58\ ft/s^2

Magnitude of acceleration while stopping is 4611.58 ft/s²

8 0
3 years ago
Can rock undergo compression, tension, and shear stress all at once?<br> explain
Katena32 [7]
This causes reverse faults<span>, which are the reverse of </span>normal faults<span>, because in this case, the hanging wall slides upward relative to the footwall. Shear </span>stress<span> is when rock slabs slide past each other horizontally. There is no vertical movement of either the hanging wall or footwall, and we get a strike-slip </span>fault<span>.</span>
7 0
3 years ago
Im stressing out about this cause obviously i thought i did good but i guess not can someone explain to me where i went wrong th
Black_prince [1.1K]

I would recommend, to include the scientific part of Newton's Laws of motion, with an example. Also, state how all three laws play a part in the activity. It seems like you just did the realistic part of it, swimming, now include how it happens with correct vocabulary.  Good Luck!

3 0
3 years ago
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