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Vlad [161]
3 years ago
12

2. The long-jump pit was recently rebuilt to make it level with the runway. Volunteers provided pieces of

Mathematics
1 answer:
lakkis [162]3 years ago
8 0

Answer:2. It’s 24.58

How many boards did the volunteers supply round your calculations to the nearest hundred- 13.44

How many whole boards-14

Step-by-step explanation:

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A baseball team has home games on Thursday and Saturday The two games together earn ​$4061.50 for the team. Thursday​'s game gen
marta [7]
The team made 2,061.50 at the first game and 2,000.00 at the second game. Because 2,000.00 would be 61.50 less than the amount made at the first game. You can check it by adding 2,061.50 + 2,000.00 which equals $4,061.50.
7 0
3 years ago
Bamboo plants grow rapidly. A bamboo plant is 130 inches tall. Tomorrow it will be 143 inches tall, the next day it will be 156
jasenka [17]

Your choice of answer D is correct.

_____

When the number of days is zero, the height is 130 inches. This eliminates choices B and C. Evaluating the expression for n=13 gives

... 130 + 13×13 = 130 + 169 = 299 . . . . . corresponding to answer D.

3 0
3 years ago
Formulate the following problem as least squares problems. For each problem, give a matrixA and a vector b such that the problem
hammer [34]

Answer:

a) A=\left[\begin{array}{ccc}1&2&3\\1&-1&1\end{array}\right]

b=\left[\begin{array}{ccc}0\\1\end{array}\right]

b) ||Ax-b||^{2} =(-bx_{2}+4)^{2}  (-4x_{1} +3x_{2} -1)^{2} +(x_{1} +8x_{2} -3)^{2}

c) A=\left[\begin{array}{ccc}0&6\sqrt{2} &0\\\sqrt{3} &3\sqrt{3} &0\\2&-16&0\end{array}\right]

x=\left[\begin{array}{ccc}x_{1} \\x_{2} \\x_{3} \end{array}\right]

b=\left[\begin{array}{ccc}-\sqrt{2} \\\sqrt{3} \\6\end{array}\right]

Step-by-step explanation:

a) considering the equation:

Minimize x_{1}^{2}  +2x_{2}x^{2}  +3x_{3}^{2}+(x_{1}   -x_{2} +x_{3} -1)^{2} +(-x_{1} -4x_{2} +2)^{2}

A=\left[\begin{array}{ccc}1&2&3\\1&-1&1\end{array}\right] (matrix A)

vector b

b=\left[\begin{array}{ccc}0\\1\end{array}\right]

b) If Pxn is matrix B and p-vector d, we have:

minimize (-6x_{2}+4)^{2}  +(-4x_{1} +3x_{2} -1)+(x_{1} +8x_{2} -3)^{2}

Ax=\left[\begin{array}{ccc}0&-6&0\\-4&3&0\\1&8&0\end{array}\right]

\left[\begin{array}{ccc}x_{1} \\x_{2} \\x_{3} \end{array}\right]

b=\left[\begin{array}{ccc}-4\\1\\3\end{array}\right]

Ax-b=\left[\begin{array}{ccc}-bx_{2}+4 \\-4x_{1}+3x_{2}-1  \\x_{1}+8x_{2}-3  \end{array}\right] =1

||Ax-b||^{2} =(-bx_{2}+4)^{2}  (-4x_{1} +3x_{2} -1)^{2} +(x_{1} +8x_{2} -3)^{2}

c) minimize 2(-bx_{2}+4)^{2}  +3(-4x_{1} +3x_{2} -1)^{2} +4(x_{1} -x_{2} -3)^{2} -(6\sqrt{2}x_{2}  +4\sqrt{2} )^{2} +(-4\sqrt{3} x_{1} +3\sqrt{3}x_{2}  -\sqrt{3})^{2}  +(2x_{1} -16x_{2} -6)^{2}

in matrix:

A=\left[\begin{array}{ccc}0&6\sqrt{2} &0\\\sqrt{3} &3\sqrt{3} &0\\2&-16&0\end{array}\right]

x=\left[\begin{array}{ccc}x_{1} \\x_{2} \\x_{3} \end{array}\right]

b=\left[\begin{array}{ccc}-\sqrt{2} \\\sqrt{3} \\6\end{array}\right]

6 0
3 years ago
Estimate the product. 22×2.4 = _×_=_ Solve using an area model and the standard algorithm. Remember to express your products in
Novay_Z [31]
It is 52.8 sorry :/ i-
7 0
3 years ago
12(3)+3y=60 solve for y​
frozen [14]

Answer: y = 8

Step-by-step explanation:

12(3)+3y=60

36 + 3y = 60

collect like terms

3y = 60-36

3y = 24

y = 24/3

y = 8

6 0
3 years ago
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