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3 years ago

8

A coffee shop orders 212 boxes of coffee each bag month if there are 68 bags of coffee age box about how many bags of coffee do

they order each month

1 answer:

icang [17]3 years ago

8 0

Just multiply....

212×68 = 14,416 bags !!

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P: x – 5 =10 q: 4x + 1 = 61 Which is the inverse of p → q?

Lesechka [4]

The inverse is b. If 4x+1 .NE. 61, then x-5 .NE.10

3 0

3 years ago

Read 2 more answers

The circumference of a sphere was measured to be 76 cm with a possible error of 0.5 cm. (a) Use differentials to estimate the ma

andreev551 [17]

The maximum error in the calculated surface area is 24.19cm² and the relative error is 0.0132.

Given that the circumference of a sphere is 76cm and error is 0.5cm.

The formula of the surface area of a sphere is A=4πr².

Differentiate both sides with respect to r and get

dA÷dr=2×4πr

dA÷dr=8πr

dA=8πr×dr

The circumference of a sphere is C=2πr.

From above the find the value of r is

r=C÷(2π)

By using the error in circumference relation to error in radius by:

Differentiate both sides with respect to r as

dr÷dr=dC÷(2πdr)

1=dC÷(2πdr)

dr=dC÷(2π)

The maximum error in surface area is simplified as:

Substitute the value of dr in dA as

dA=8πr×(dC÷(2π))

Cancel π from both numerator and denominator and simplify it

dA=4rdC

Substitute the value of r=C÷(2π) in above and get

dA=4dC×(C÷2π)

dA=(2CdC)÷π

Here, C=76cm and dC=0.5cm.

Substitute this in above as

dA=(2×76×0.5)÷π

dA=76÷π

dA=24.19cm².

Find relative error as the relative error is between the value of the Area and the maximum error, therefore:

$\begin{aligned}\frac{dA}{A}&=\frac{8\pi rdr}{4\pi r^2}\\ \frac{dA}{A}&=\frac{2dr}{r}\end$

As above its found that r=C÷(2π) and r=dC÷(2π).

Substitute this in the above

$\begin{aligned}\frac{dA}{A}&=\frac{\frac{2dC}{2\pi}}{\frac{C}{2\pi}}\\ &=\frac{2dC}{C}\\ &=\frac{2\times 0.5}{76}\\ &=0.0132\end$

Hence, the maximum error in the calculated surface area with the circumference of a sphere was measured to be 76 cm with a possible error of 0.5 cm is 24.19cm² and the relative error is 0.0132.

Learn about relative error from here brainly.com/question/13106593

#SPJ4

3 0

2 years ago

Help me with fractions. Please look at the picture before solving. Circle 1/5 of all the triangles. Mark X's on 2/3 of the trian

Irina-Kira [14]

1/5 are 3 triangles
2/3 are 10 triangles

6 0

3 years ago

Read 2 more answers

I don't get it and I have tried it multiple ways

jasenka [17]

9514 1404 393

Answer:

9350 m²

Step-by-step explanation:

There are several ways you can go at this. Here are 3 of them:

along an extension of the lower right vertical edge, divide the figure into a rectangle and a right triangle.
between the upper left corner and the inside corner at lower right draw a diagonal line to divide the figure into a trapezoid and a triangle.
subtract the area of the trapezoid at the right from the area of the bounding rectangle

__

The relevant formulas for area are ...

rectangle: A = LW . . . . . . . . . . . length times width

trapezoid: A = (1/2)(b1 +b2)h . . . b1, b2 are the bases, h is the height

triangle: A = (1/2)bh . . . . . . . . . . . b is the base, h is the height

__

Here's what those computations look like:

1. rectangle: 60m wide by 80 m high = 4800 m².

right triangle: base 190-60 = 130 m; height = 80-10 = 70 m.

area = (1/2)(130 m)(70 m) = 4550 m²

figure area = 4800 m² +4550 m² = 9350 m² . . . . area of figure

__

2. The trapezoid has bases of 80 m and 10 m, and a height of 60 m. Its area is ...

A = (1/2)(80 m +10 m)(60 m) = 2700 m²

The triangle has a base of 190 m and a height of 80-10 = 70 m. Its area is ...

A = (1/2)(190 m)(70 m) = 6650 m²

Then the total area is 2700 m² +6650 m² = 9350 m² . . . total area

__

3. The bounding rectangle is 190 m by 80 m, so its area is ...

A = LW = (190 m)(80 m) = 15200 m²

The (negative) trapezoid at right has bases of 10 m and 80 m, and a width of 190-60 = 130 m. Its area is ...

A = (1/2)(10 m +80 m)(130 m) = 5850 m²

The area of the figure is the difference between these:

figure area = 15200 m² -5850 m² = 9350 m² . . . figure area

7 0

3 years ago

If line A contains the points (3, -4) and (6, -2), and line B contains the points (-1, 5) and (1, 2), prove that the lines are p

vivado [14]

Answer:

Correct answer: sa · sb = 2/3 · (- 3/2) = - 1

Step-by-step explanation:

Given:

line A - (x₁, y₁) = (3, -4) and (x₂, y₂) = (6, -2)

line B - (x₁, y₁) = (-1, 5) and (x₂, y₂) = (1, 2)

The slope is calculated using the following formula:

s = (y₂ - y₁) / (x₂ - x₁)

sa = (-2 - (-4)) / (6 - 3) = (-2 + 4) / 3 = 2 / 3

sa = 2 / 3

sb = (2 - 5) / (1 - (-1)) = -3 / 2

when lines are perpendicular to each other then the slopes are in the next relationship:

sa · sb = - 1

we will check:

sa · sb = 2/3 · (- 3/2) = - 1

God is with you!!!

7 0

3 years ago