Answer: 180
Step-by-step explanation:
A (2^2/2^-1)is the correct answer because 2^-5 * 2^8 = 8 and 2^2/2^-1 = 8.
Answer:
Hence, the equation of a sphere with one of its diameters with endpoints (-9, -12, -6) and (11, 8, 14) is
.
Step-by-step explanation:
There are two kew parameters for a sphere: Center (
,
,
) and Radius (
). The radius is the midpoint of the line segment between endpoints. That is:
![C(x,y,z) = \left(\frac{-9+11}{2},\frac{-12+8}{2},\frac{-6+14}{2} \right)](https://tex.z-dn.net/?f=C%28x%2Cy%2Cz%29%20%3D%20%5Cleft%28%5Cfrac%7B-9%2B11%7D%7B2%7D%2C%5Cfrac%7B-12%2B8%7D%7B2%7D%2C%5Cfrac%7B-6%2B14%7D%7B2%7D%20%20%20%5Cright%29)
![C(x,y,z) = (1,-2,4)](https://tex.z-dn.net/?f=C%28x%2Cy%2Cz%29%20%3D%20%281%2C-2%2C4%29)
The radius can be found by halving the length of diameter, which can be determined by knowning location of endpoints and using Pythagorean Theorem:
![r = \frac{1}{2}\cdot \sqrt{(-9-11)^{2}+(-12-8)^{2}+(-6-14)^{2}}](https://tex.z-dn.net/?f=r%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20%5Csqrt%7B%28-9-11%29%5E%7B2%7D%2B%28-12-8%29%5E%7B2%7D%2B%28-6-14%29%5E%7B2%7D%7D)
![r = 10\sqrt{3}](https://tex.z-dn.net/?f=r%20%3D%2010%5Csqrt%7B3%7D)
The general formula of a sphere centered at (h, k, s) and with a radius r is:
![(x-h)^{2}+(y-k)^{2}+(z-s)^{2} = r^{2}](https://tex.z-dn.net/?f=%28x-h%29%5E%7B2%7D%2B%28y-k%29%5E%7B2%7D%2B%28z-s%29%5E%7B2%7D%20%3D%20r%5E%7B2%7D)
Hence, the equation of a sphere with one of its diameters with endpoints (-9, -12, -6) and (11, 8, 14) is
.
Answer:
:)
Step-by-step explanation:
SINCE THATS AN ISOSCELES TRIANGLE:
AB=BC
SO 3x-4=5x-10
But we have to find x
3x-4=5x-10
Minus 3x on both sides
-4=2x-10
Add 10 on both sides
6=2x
Divide 2 on both sides
3=x
So x is 3
Now since we are looking for side AB which is 3x-4
Substitute in 3 as x
3(3)-4
9-4=5
So 5 is the answer.
Brainlist would be much appreciated!