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Morgarella [4.7K]
3 years ago
8

8.(01.02)

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
6 0

Answer:

Step-by-step explanation:

so the g(x) = x-1 gets plugged into every  x in the f(x) function

=(x-1)^{2} - 3(x-1) + 3

=x^{2}-2x+1 -3x +3 + 3

=x^{2} -5x +7

now plug in x = 5

=5^{2} -5(5) +7

= 7

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A teacher buys packs of notebooks to give to his students. The ratio of gold notebooks to red notebooks is represented in the ta
Naddika [18.5K]

Answer:

there would be 40 gold notebooks

Step-by-step explanation:

if the ratio is 5g to 3r i took the 24 red and divided it by 3 which gave me 8. I then multiplied 8 by 5 and got 40. so 40:24 is equal to 5:3

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HELP PLEASE WITH EXPLANATION
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So hmm notice the picture below

that's the 30-60-90 rule, notice your triangle, the bottom-left-angle is a right angle, 90°, the angle atop is 30°, so the angle on the bottom-right has to be 60°, thus is a 30-60-90 triangle, and as you can see on the triangle on the left in the picture, those are the ratios for it

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3 years ago
What is the value of this expression <br>5+(5-9)^2+3(16÷8)​
kaheart [24]

Answer:

27/4 or 6 3/4

Step-by-step explanation:

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3 0
2 years ago
Read 2 more answers
I need to get the left side to equal the right side. Keeping the right side alone and not changing it.
likoan [24]

<u>To prove the trigonometric equation:</u>

\sin ^{3} x+\cos ^{3} x=(\sin x+\cos x)(1-\sin x \cos x)

RHS=(\sin x+\cos x)(1-\sin x \cos x)

We know that \sin^2x +\cos^2x=1, substitute this in place of 1.

       =(\sin x+\cos x)(\sin^2x +\cos^2x-\sin x \cos x)

Multiply each term of the first term with each term of the 2nd term.

       =\sin^3x + \sin x \cos^2x-\sin^2 x \cos x+\cos x \sin^2 x + \cos^3 x-\sin x\cos^2 x

Group like terms together.

       =\sin^3x +( \sin x \cos^2x-\sin x\cos^2 x)+(\cos x \sin^2 x-\sin^2 x \cos x) + \cos^3 x

       =\sin^3x +( 0)+(0) + \cos^3 x

       =\sin^3x + \cos^3 x

       = LHS

RHS = LHS

\sin ^{3} x+\cos ^{3} x=(\sin x+\cos x)(1-\sin x \cos x)

Hence proved.

7 0
3 years ago
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