Answer:
x = 9
Step-by-step explanation:
set a proportion: 8/12 = 6/x => 8x = 72 => x = 9
Answer:
-1/8
Step-by-step explanation:
First, lets create a equation for our situation. Let

be the months. We know four our problem that <span>Eliza started her savings account with $100, and each month she deposits $25 into her account. We can use that information to create a model as follows:
</span>

<span>
We want to find the average value of that function </span>from the 2nd month to the 10th month, so its average value in the interval [2,10]. Remember that the formula for finding the average of a function over an interval is:

. So lets replace the values in our formula to find the average of our function:
![\frac{25(10)+100-[25(2)+100]}{10-2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B25%2810%29%2B100-%5B25%282%29%2B100%5D%7D%7B10-2%7D%20)



We can conclude that <span>the average rate of change in Eliza's account from the 2nd month to the 10th month is $25.</span>
Answer:


Step-by-step explanation:
The recursive rule is a term defined in terms of other terms in the sequence.
The is a geometric sequence because it has a common ratio.
The common ratio can be found by dividing a term by previous term.
For example, all of these are equal:



They are all equal to
.
So we are saying:

More formally:
.
Multiply both sides by
:

When doing recursive form, you need to state a term of the sequence (or more depending on the recursive form you have).
So the first term is 2.
So the full thing for the answer is:

