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3 years ago

Find the slope of the line graphed below

Mathematics

1 answer:

Korolek [52]3 years ago

4 0

Answer:

Slope = 1

Step-by-step explanation:

(x1, y1) = (-5, -3)

(x2, y2) = (-1, 1)

(y2 - y1) / (x2 - x1) = (1 - -3) / (-1 - -5) = 4 / 4 = 1

Slope = 1

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A person borrowed Rs. 5550 from is at 4% compound interest Rs 500 was paid each year. what amount paid at the end of 5th year wi

nordsb [41]

Solution :

Money left after 1st year :

$M = 5550( 1 + \dfrac{4}{100}) - 500 = 5272$

Money left after 2nd year :

$M = 5272( 1 + \dfrac{4}{100}) - 500 = 4982.88$

Money left after 3rd year :

$M = 4982.88( 1 + \dfrac{4}{100}) - 500 = 4682.19$

Money left after 4rd year :

$M = 4682.19( 1 + \dfrac{4}{100}) - 500 = 4369.48$

Money left after 5rd year :

$4369.48(1+\dfrac{4}{100})-500 = 4044.26$

At the end of 5th year an amount of Rs 4044.26 will clear the debt.

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3 years ago

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The two lines intersect at the point (4,-1)

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3 years ago

An old nickel has doubled in value each decade. What is the value of the coin after 10 decades?

Lubov Fominskaja [6]

Answer:

100

Step-by-step explanation:

10 x 10

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3 years ago

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3 years ago

Two methods, A and B, are available for teaching a certain industrial skill. The failure rate is 15% for A and 5% for B. However

baherus [9]

Answer:

P(A | F) = 81.81%

There is 81.81% probability that worker was taught by method A given that he failed to learn it correctly.

Step-by-step explanation:

The failure rate is 15% for A which means that

P(F | A) = 0.15

The failure rate is 5% for B which means that

P(F | B) = 0.05

Method B is more expensive and hence is used only 40% of the time which means that

P(B) = 0.40

Which means that A is used the other 60% of the time

P(A) = 0.60

A worker is taught the skill by one of the methods but fails to learn it correctly.

We are asked to find the the probability that he was taught by method A.

So that means we want to find out

P(A | F) = ?

We know that according to Baye's rule,

$P(A \:|\: F) = \frac{P(F \:|\: A)\times P(A) }{P(F \:|\: A)\times P(A) + P(F \:|\: B)\times P(B) }$

Substitute the given probabilities into the above equation

$P(A \:|\: F) = \frac{0.15\times 0.60 }{0.15\times 0.60 + 0.05\times 0.40}\\\\P(A \:|\: F) = \frac{0.09 }{0.09 + 0.02}\\\\P(A \:|\: F) = 0.8181 \\\\P(A \:|\: F) = 81.81\%$

Therefore, there is 81.81% probability that worker was taught by method A given that he failed to learn it correctly.

7 0

4 years ago