Copper Atoms in 149 Kg pure Cu(s) = <span>1.41×<span>1027</span></span><span> Cu atoms.</span>
Answer:-
0.229 L
Explanation:-
Molar mass of AgBr = 107.87 x 1 + 79.9 x 1
=187.77 grams mol-1
Mass of AgBr = 150 grams
Number of moles of AgBr = 150 grams / 187.77 gram mol-1
= 0.8 mol
The balanced chemical equation is
NaBr (aq) + AgNO3 (aq)--> AgBr(s) + NaNO3(aq)
From the equation we can see that
1 mol of AgBr is produced from 1 mol of AgNO3.
∴ 0.8 mol of AgBr is produced from 1 x 0.8 / 1 = 0.8 mol of AgNO3.
Strength of AgNO3 = 3.5 M
Volume of AgNO3 required = Number of moles / strength
= 0.8 moles / 3.5
=0.229 L
Answer:
pCH4 = 0.9184 atm
pCCl4 = 0.9184 atm
pCH2Cl2 = 0.2832 atm
Explanation:
Step 1: Data given
The equilibrium constant, Kp= 9.52 * 10^-2
Temperature = 350 K
Each have an initial pressure of 1.06 atm
Step 2: The balanced equation
CH4(g) + CCl4(g) ⇆ 2CH2Cl2(g)
Step 3: The pressure at the equilibrium
pCH4 = 1.06 - X atm
pCCl4 = 1.06 - X atm
pCH2Cl2 = 2X
Step 4: Calculate Kp
Kp = (2X)² / (1.06 - X)*(1.06 - X)
9.52 * 10^-2 = 4X² / (1.06 - X)*(1.06 - X)
X = 0.1416
Step 5: Calculate the partial pressure
pCH4 = 1.06 - 0.1416 = 0.9184 atm
pCCl4 = 1.06 - 0.1416 = 0.9184 atm
pCH2Cl2 = 2 * 0.1416 = 0.2832 atm
Kp = (0.2832²) / (0.9184*0.9184)
Kp = 9.52 * 10^-2
pCH4 = 0.9184 atm
pCCl4 = 0.9184 atm
pCH2Cl2 = 0.2832 atm
<h3>
Answer:</h3>
4 g AgCl
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Stoichiometry</u>
- Reading a Periodic Table
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[RxN] 2AgNO₃ + BaCl₂ → 2AgCl + Ba(NO₃)₂
[Given] 5.0 g AgNO₃
<u>Step 2: Identify Conversions</u>
[Reaction - Stoich] 2AgNO₃ → 2AgCl
Molar Mass of Ag - 107.87 g/mol
Molar Mass of N - 14.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of Cl - 35.45 g/mol
Molar Mass of AgNO₃ - 107.87 + 14.01 + 3(16.00) = 169.88 g/mol
Molar Mass of AgCl - 107.87 + 35.45 = 143.32 g/mol
<u>Step 3: Stoichiometry</u>
- Set up:
- Multiply/Divide:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 1 sig fig.</em>
4.21533 g AgCl ≈ 4 g AgCl
A magnesium atom is a neutral atom where the number of protons and electrons are the same. A magnesium ion has a positve 2 charge since it will lose two of its electrons when it undergoes ionic bonding. Since it's the same element it will still have the same amount of 12 protons. For isotopes of magnesium, they will have differing amounts of neutrons and thus a difference in the mass number since neutrons have a mass of about 1
