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HACTEHA [7]
3 years ago
11

Write each number in standard notation

Chemistry
2 answers:
Agata [3.3K]3 years ago
8 0
21. 26600
22. .015
23. .775
24. 83000000
25. 95000000
26. 171000000
27. 0009 
just move the decimal points and add zeros its pretty simple and remember google exists and so does a calculator!! :)
alexandr402 [8]3 years ago
5 0
21. 26,600
22. 0.015
23. 0.775
24. 83,000,000
25. 95,000,000
26. 17,100,000
27. 0.0009
28. 3,800
29. 0.000075
30. 4
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I need help balancing both equations?
erik [133]

Answer:

6CO2 + 6H2O --> C6H12O6 + 6O2

C6H12O6 + O2 --> 6CO2 + 6H2O

Explanation:

The balanced form of both equations

5 0
3 years ago
Your local grocery store
umka2103 [35]

The total number of matchbooks required would 5,000 be and the cost would be $144

<h3>Mathematical ratios</h3>

50 matchbooks = $1.44

Each matchbook = 0.005 grams red phosphorus

25 grams of red phosphorus is needed:

                                 25/0.005 = 5,000 matchbooks

5,000 matchbooks will cost:

                         5000/50 x 1.44 = $144

More on mathematical ratios can be found here: brainly.com/question/20387079

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3 0
2 years ago
What is the correct electron configuration for copper?
kakasveta [241]

Answer:

[Ar] 3d10 4s1

Explanation:

The correct electronic configuration of copper is [Ar] 3d10 4s1

Copper has atomic number 29 and due to the stability of half filled or fully filled orbitals or shells, the electrons from the 4s jumps to the 3d and makes the 3d shell contain 10 electrons.

This is what I mean:

Cu = Ar 4s2 3d10 is the expected configuration of copper when we follow the principle of filling the various orbitals that is the s, p, d, f orbitals.

But because we write 3d before writing 4s, we have Ar 3d10 4s2. Instead of this configuration becoming the correct one, an electron from the 4s orbital jumps to the 3d orbital to complete the orbital giving the electrons in the 3d orbital 10.

So therefore the correct configuration is Ar 3d10 4s1

4 0
3 years ago
Is platinum an element or compound
user100 [1]
Platinum, symbol Pt is an element
7 0
3 years ago
URGENT!!!
miv72 [106K]
<h3>Answer;</h3>

= 13.629 g of ZnCl2

<h3><u>Explanation;</u></h3>

The equation for the reaction.

Zn(s)+2HCL(aq)=>ZnCl2(aq)+H2(g)

Number of moles of Zinc;

Moles = mass/RAM

          = 6.5 g/65g/mol

          = 0.1 moles

The mole ration of Zn : ZnCl2 is 1 : 1

Therefore, number of moles of ZnCl2 is 0.1 moles

Mass = moles × Molar mass

         = 0.1 ×136.286 g/mol

        <u> = 13.629 g</u>

7 0
3 years ago
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