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Citrus2011 [14]

3 years ago

14

X^2+27x how to get this to equal zero

1 answer:

WARRIOR [948]3 years ago

4 0

Answer:

x=0

x=-27

Step-by-step explanation:

x^2+27x = x ( x + 27)

any of both terms of the product, should be equal to zero, so

x=0, or

x=-27

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9(2x+9) <br> Help me please !

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Answer:

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Step-by-step explanation:

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3 years ago

Tell whether the figure is a polygon. If it is a polygon, name it by the number of its sides.

never [62]

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2 years ago

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A right △ABC is inscribed in circle k(O, r). Find the radius of this circle if:

natta225 [31]

We have been given that a right △ABC is inscribed in circle k(O, r).

m∠C = 90°, AC = 18 cm, m∠B = 30°. We are asked to find the radius of the circle.

First of all, we will draw a diagram that represent the given scenario.

We can see from the attached file that AB is diameter of circle O and it a hypotenuse of triangle ABC.

We will use sine to find side AB.

$\text{sin}=\frac{\text{Opposite}}{\text{Hypotenuse}}$

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4 years ago

<img src="https://tex.z-dn.net/?f=9%28x%2B1%29%20-4x%20%3D%205-%28x-3%29" id="TexFormula1" title="9(x+1) -4x = 5-(x-3)" alt="9(x

nekit [7.7K]

Answer:

$x=\frac{-1}{6}$

Step-by-step explanation:

$9(x+1) -4x = 5-(x-3)$

$9(x+1) -4x = 5-(x-3) \\$

$9x+9\cdot1-4x=5-\left(x-3\right)$

$9x+9-4x=5-\left(x-3\right)$

$\left(9x-4x\right)+9=5-\left(x-3\right)$

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$5x+9=-x+\left(5+3\right)$

$5x+9=-x+8$

$5x+9=-x+8$

$5x+9+x=-x+8+x$

$5x+x+9=-x+8+x$

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$6x+9=-x+x+8$

$6x+9=8$

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$x=\frac{-1}{6}$

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3 years ago

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