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Citrus2011 [14]
3 years ago
14

X^2+27x how to get this to equal zero

Mathematics
1 answer:
WARRIOR [948]3 years ago
4 0

Answer:

x=0

x=-27

Step-by-step explanation:

x^2+27x = x ( x + 27)

any of both terms of the product, should be equal to zero, so

x=0, or

x=-27

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Factor the polynomial below. 4x^2-16 A. 4(x + 2)(x - 2) B. 4(x - 2)2 C. 4(2 - x)2 D. 4(2 + x)(2 - x)
marusya05 [52]

Answer:

Option A, 4(x + 2)(x - 2)

Step-by-step explanation:

<u>Step 1:  Pull out a 4 </u>

<em>4(x^2 - 4) </em>

<u>Step 2:  Factor x^2 - 4 </u>

x^2 - 4

<em>(x + 2)(x - 2) </em>

<u>Step 3:  Combine </u>

<em>4(x + 2)(x - 2) </em>

Answer:  Option A, 4(x + 2)(x - 2)

3 0
4 years ago
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If it takes 5 gallons of gas to drive 115 miles, how many miles can be driven using 7 gallons of gas?
elena-s [515]

Answer: The answer is 161

Step-by-step explanation: First you write 5 and 115 as a proportion, 5/115, (for every 5 gallons you can go 115 miles). Then you find out how much you can go with 1 gallon, divide by 5. Then multiply that by 7, since that is how many gallons you need to find out.

Hope this is helpful!

7 0
4 years ago
Write the 5th term in the expansion of (5x-y/2)^7
Nezavi [6.7K]

Answer:

65625/4(x^5)(y²)

Step-by-step explanation:

Using binomial expansion

Formula: (n k) (a^k)(b ^(n-k))

Where (n k) represents n combination of k (nCk)

From the question k = 5 (i.e. 5th term)

n = 7 (power of expression)

a = 5x

b = -y/2

....................

Solving nCk

n = 7

k = 5

nCk = 7C5

= 7!/(5!2!) ------ Expand Expression

=7 * 6 * 5! /(5! * 2*1)

= 7*6/2

= 21 ------

.........................

Solving (a^k) (b^(n-k))

a = 5x

b = -y/2

k = 5

n = 7

Substituting these values in the expression

(5x)^5 * (-y/2)^(7-5)

= (3125x^5) * (-y/2)²

= 3125x^5 * y²/4

= (3125x^5)(y²)/4

------------------------------------

Multiplying the two expression above

21 * (3125x^5)(y²)/4

= 65625/4(x^5)(y²)

5 0
3 years ago
HELP FAST I NEED ANSWER ASAP I will give brainliest <br> A. 1/2<br> B. 1/3<br> C. 1/4<br> D. 1/5
suter [353]

1/3 hope this helps ive tooken the test

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4 years ago
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Inga [223]

Answer:

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