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4 years ago

If it takes 5 gallons of gas to drive 115 miles, how many miles can be driven using 7 gallons of gas?

Mathematics

1 answer:

elena-s [515]4 years ago

7 0

Answer: The answer is 161

Step-by-step explanation: First you write 5 and 115 as a proportion, 5/115, (for every 5 gallons you can go 115 miles). Then you find out how much you can go with 1 gallon, divide by 5. Then multiply that by 7, since that is how many gallons you need to find out.

Hope this is helpful!

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Galina-37 [17]

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FrozenT [24]

Answer:

$A=2\sqrt{14}\ units^2$

Step-by-step explanation:

we know that

Heron's Formula is a method for calculating the area of a triangle when you know the lengths of all three sides.

$A=\sqrt{s(s-a)(s-b)(s-c)}$

where

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<em>Find the semi-perimeter s </em>

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3 years ago

I need to find side x in its simplest radical form using the special right triangles method

crimeas [40]

Answer:

\sqrt{6}

Explanation:

From the given diagram,

Hypotenuse sde = x

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Using the SOH CAH TOA identity

Sintheta = opposite/hypotenuse

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x = \sqrt{3}/sin45

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5 0

1 year ago

Suppose ABC is a right triangle with sides a, b, and c and right angle at C. Find the unknown side length using the Pythagorean

Leno4ka [110]

Answer:

a = $\sqrt{7}$

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.:

<em>Suppose ABC is a right triangle with sides a, b, and c and right angle at C. Find the unknown side length using the Pythagorean theorem and then find the values of the six trigonometric functions for angle B. when b=3 and c=4</em>.

My answer:

We will Pythagoras theorem, which states that the sum of squares of two legs of a right triangle is equal to the square of the hypotenuse of right triangle. Because the question says that ABC is a right triangle.

$a^2+b^2=c^2$

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$a^2+3^2=4^2a^2+9=16a^2+9-9=16-9a^2=7$

so a = $\sqrt{7}$

We know that tangent relates opposite side of a right triangle with adjacent side.

$\text{tan}(B)=\frac{a}{b}\\\text{tan}(B)=\frac{\sqrt{7}}{3}$

Please have a look at the attached photos.

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