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Inessa [10]
3 years ago
11

The word that is associated with doing something to help protect something is —

Mathematics
2 answers:
Natalka [10]3 years ago
4 0
The answer is C I’m pretty sure
tamaranim1 [39]3 years ago
3 0
The answer is c i’m pretty sure
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Can you Afford to Enlarge this?You each want to have a 3" X 5' picture ofprinted so that you canput it on your dartboard. It cos
Marizza181 [45]

Given:

\text{ Dimension = 3}\times5

Sol:

Area of picture is:

\begin{gathered} =\text{ length}\times\text{ Width} \\  \\ =15 \end{gathered}

If the cost $10 per square inch then price of 15 square inch is:

\begin{gathered} =15\times10 \\  \\ =150 \end{gathered}

If the quadruple of dimension that mean:

\begin{gathered} \text{ l ength = 4 length} \\  \\ Width\text{ = 4 width} \end{gathered}

So area is:

\begin{gathered} A=4\text{ length}\times4\text{ Width} \\  \\ A=4(15) \\  \\ A=60 \end{gathered}

So price is:

\begin{gathered} =60\times10 \\  \\ =600 \end{gathered}

3 0
1 year ago
Use quadratic equation to find the roots of the following equations
sertanlavr [38]
See the attachment below.

Hope it helps!

3 0
3 years ago
Read 2 more answers
A lake currently has a depth of 30 meters. As sediment builds up in the lake, its depth decreases by 2% per year. This situation
lubasha [3.4K]

Answer:

This situations represents the depth of the lake after t years.

The rate of decay is equal to 0.02 a year.

So the depth of the lake each year is 0.98 times the depth in the previous year.

It will take 5.77 years for the depth of the lake to reach 26.7 meters.

Step-by-step explanation:

Exponential equation of decay:

The exponential equation for the decay of an amount is given by:

D(t) = D(0)(1-r)^t

In which D(0) is the initial amount and r is the decay rate, as a decimal.

A lake currently has a depth of 30 meters. As sediment builds up in the lake, its depth decreases by 2% per year.

This means that D(0) = 30, r = 0.02

So

D(t) = D(0)(1-r)^t

D(t) = 30(1-0.02)^t

D(t) = 30(0.98)^t

This situation represents

The depth of the lake after t years.

The rate of growth or decay, r, is equal to

The rate of decay is equal to 0.02 a year.

So the depth of the lake each year is times the depth in the previous year.

1 - 0.02 = 0.9

So the depth of the lake each year is 0.98 times the depth in the previous year.

It will take between years for the depth of the lake to reach 26.7 meters.

This is t for which D(t) = 26.7. So

D(t) = 30(0.98)^t

26.7 = 30(0.98)^t

(0.98)^t = \frac{26.7}{30}

\log{(0.98)^t} = \log{\frac{26.7}{30}}

t\log{(0.98)} = \log{\frac{26.7}{30}}

t = \frac{\log{\frac{26.7}{30}}}{\log{0.98}}

t = 5.77

It will take 5.77 years for the depth of the lake to reach 26.7 meters.

4 0
3 years ago
Need help with this math question
Bogdan [553]

Answer: w = 61

Step-by-step explanation:

If the wall is 456 cm then the carpenter has already used up 334 cm of the wall on the other book cases. So 456-334 = 122 and since both of the bookcases are going to be the same width you divide 122 by 2 which gives you 61. Hope this helps :).

5 0
4 years ago
Which expression is the completely factored form of x6−64y3 ? (x2−4y)(x4−16y2) (x2−4y)3 (x2−4y)(x4+4x2y+16y2) (x2+4y)(x4−4x2y+16
horrorfan [7]
(x^2 - 4y)(x^4 + 4x^2 y + 16y^2)
4 0
3 years ago
Read 2 more answers
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