Answer:

Step-by-step explanation:
I accept your challenge!
First we know that a equation of the line is a linear equation, and its equation is:


In this context, the slope, defined as the steepness of a line is characterized as the ratio of RISE (the difference in the y-coordinates, the vertical change) over the RUN (the difference in x-coordinates, the horizontal change).

Once we know two points where the line goes through, we can get the slope, once we know the change in y and x.
I will take
as Point 1 and
as Point 2.
So, 


Now we have to find the y-intercept:
To do so, think about the the points given and the nearly finished equation, we can find b with those two informations.
Our currently equation of the line is:

Using the points, take Point 1 as an example, it says that when
, so plugging it in the equation:

Taking the Point 2

Now we found
! The equation is complete!
