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Elden [556K]
3 years ago
6

​ 13(21−3a)=6−a​ no solution −1 0 all real numbers

Mathematics
2 answers:
mel-nik [20]3 years ago
7 0
<span>1/3(21−3a)=6−a
distribute 1/3 to all factors in the parenthesis
7 - a = 6 - a
add "a" to both sides
7 = 6
This is not true, there are NO solutions to this equation...</span>
love history [14]3 years ago
4 0

Answer:

No solution hope this helps:)

Step-by-step explanation:

You might be interested in
Chelsea and her friends are making small fruit baskets for their neighbors. They have 90 pears, 45 peaches, and 75 apples. What
iVinArrow [24]

Answer:

15 baskets

Step-by-step explanation:

This question is a GCF question

The first step would be to find the factors of 45, 75 and 90

The factors of 45 are: 1, 3, 5, 9, 15, 45

The factors of 75 are: 1, 3, 5, 15, 25, 75

The factors of 90 are: 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90

The greatest common factor is 15.

Therefore, the greatest number of baskets they can make if each basket has the same number of pears, the same number of peaches, and same number of apples, with no fruit leftover is 15 baskets

3 0
3 years ago
HELP PLEASE THANKS:(
astraxan [27]
2(2)+3y=13
4+3y=13
3y=9
y=3
The answer is B
6 0
3 years ago
A museum opened at 9:00 a.m. In the first hour, 350 people purchased admission tickets. In the second hour, 20% more people purc
Furkat [3]

Answer:

13,475

Step-by-step explanation:

First hour

350 people at $17.50 per ticket

350* $17.50 =$6125

Second hour

We add 20% more

350+350*.20 =350+70 =420

There were 420 people at $17.50

420*$17.50 =$7350

Add the total for the 2 hours

6125+7350=13,475

3 0
3 years ago
Read 2 more answers
*Please help and explain Chebyshev's Theorem in answer.*
Leviafan [203]

Answer:

56%

Step-by-step explanation:

4 0
3 years ago
The number of "destination weddings" has skyrocketed in recent years. For example, many couples are opting to have their wedding
Andru [333]

Answer:

There is no sufficient evidence to support the claim that wedding cost is less than $30000.

Step-by-step explanation:

Values (x) ∑(Xi-X)^2

----------------------------------

29.1                    0.1702

28.5                  1.0252

28.8                  0.5077

29.4                   0.0127

29.8                  0.0827

29.8                  0.0827

30.1                   0.3452

30.6                   1.1827

----------------------------------------

236.1                 3.4088

Mean = 236.1 / 8 = 29.51

S_{x}=\sqrt{3.4088/(8-1)}=0.6978

Statement of the null hypothesis:

H0: u ≥ 30 the mean wedding cost is not less than $30,000

H1: u < 30 the mean wedding cost is less than $30,000

Test Statistic:

t=\frac{X-u}{S/\sqrt{n}}=\frac{29.51-30}{0.6978/\sqrt{8}}= \frac{-0.49}{0.2467}=-1.9861

Test criteria:

SIgnificance level = 0.05

Degrees of freedom = df = n - 1 = 8 - 1 = 7

Reject null hypothesis (H0) if

t

Finding in the t distribution table α=0.05 with df=7, we have

t_{0.05,7}=2.365

t>-t_{0.05,7} = -1.9861 > -2.365

Result: Fail to reject null hypothesis

Conclusion: Do no reject the null hypothesis

u ≥ 30 the mean wedding cost is not less than $30,000

There is no sufficient evidence to support the claim that wedding cost is less than $30000.

Hope this helps!

5 0
3 years ago
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