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Len [333]
2 years ago
12

Find the Mean, Median & Mode: 2, 6, 15, 3, 1, 8, 7

Mathematics
2 answers:
Marat540 [252]2 years ago
3 0

Answer:

There is no mode

Step-by-step explanation:

Elodia [21]2 years ago
3 0

Answer: mean is 46 median is 6  

Step-by-step explanation:

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What is the rule for the following sequence: 2, 9, 21, 65
Helga [31]

There is no common ratio or common difference. The first three terms increases more slowly than a cubic, but the last three increase more quickly than the cube of n. The pattern is not obvious to me. When the sequence is cast in recursive terms, you get

... a[n] = (48/13)a[n-2] + (59/39)a[n-1] . . . . a[1] = 2, a[2] = 9

The next term using this rule is 174 34/39, not an integer.

The coefficients p and q for a[n-2] and a[n-1] can be found from

2p+9q=21\\9p+21q=65

_____

Any sequence of 4 numbers can be matched by a polynomial of degree 3 or less. Here, a calculator's polynomial regression function tells us the rule could be

... a[n] = 4.5n³ -24.5n² +49n -27

Using this rule, the next two terms are 168 and 357.

5 0
3 years ago
Please help. Will give brainliest to correct answer.
mr Goodwill [35]

Answer:

Step-by-step explanation:

B

3 0
2 years ago
Read 2 more answers
Solve the equation x/5 =9
Elena L [17]

Answer:

x = 45

Step-by-step explanation:

Given

\frac{x}{5} = 9

Multiply both sides by 5

x = 5 × 9 = 45

7 0
3 years ago
Read 2 more answers
I am not sure about this problem?
uranmaximum [27]
The answer for your question is 4x^2-15x+6+ 2/3x+5
3 0
3 years ago
How many 4-digit odd numbers can you make using the digits 1 to 7 if the numbers must be less than 6000? No digits are repeated.
bixtya [17]

Answer:

Step-by-step explanation:he first digit must be a 6, 7, or 8, because the number has to be bigger than 6,000.

The last digit must be a 1, 3, 5, or 7, because the number has to be odd.

So if the first digit is 6 or 8, there are 4 odd-number options for the last digit. If the first digit is a 7, then there are only 3 options for the last digit, as 7 can’t be used twice.

The other two digits can be anything that’s not already used. So for each first-and-last combination of digits mentioned above, there will be six options available for one of the middle digits, and then for each of those 3-digit combinations, five options will be available for the final remaining digit.

At this point, we have everything we need to express this as an equation:

x = (2 x 4 + 1 x 3) x 6 x 5

And then we can simplify and solve:

x = (8 + 3) x 30

x = 11 x 30

x = 330

6 0
2 years ago
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