Answer:
5.1 days
Step-by-step explanation:
Given in the question,
initial amount of substance = 34 grams
k-value = 0.137
To find the half life of this substance we will use following formula
here N(0) is initial amount of substance
t is time in days
Plug values in the formula
1/2 = e^{-0.137t}
Take logarithm on both sides
ln(1/2) = ln( e^{-0.137t})
ln(1/2) = -0.137t
t = ln(1/2) / -0.137
t = 5.059
t ≈ 5.1 days (nearest to tenths)
Your answer would be x = 3.0645
CHECK
log (3.0645 + 1) ?=? -(3.0645)2 + 10
log 4.0645 ?=? -9.3912 + 10
0.609 ?=? 0.609
Hope this helps!
So in short your answer is x = 3.0645
Answer:
-2/9
Step-by-step explanation:
first you are going to distrubute 2/5, so 2/5 times x is 2/5x and 2/5 times -2 is -4/5
next you set up the problem with those two answers which gives you:
2/5x - 4/5 = 4x
then multiply both sides of the equation by 5: 2x-4=20x
next move the constant to the right side and chnage the sign: 2x=20x+4
then combine like terms: -18x=4
after that divide both sides of the equation by -18: -2/9
so x= -2/9
