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3 years ago

Gor is running a bakery. He has made a street sign to direct people to his

Mathematics

1 answer:

lys-0071 [83]3 years ago

7 0

Answer:

Step-by-step explanation:

The street sign is composed of two rectangles and 1 triangle.

Painted area = area of triangle + area of rectangle 1 + area of square

✔️Area of triangle = ½bh

b = 15 in.

h = 8 in.

Area of triangle = ½*15*8 = 60 in.²

✔️Area of rectangle 1 = L*W

L = 50 in.

W = 6 in.

Area = 50*6 = 300 in.²

✔️Area of Square = s²

s = 15 in.

Area = 15² = 255 in.²

✅Painted area = 60 + 300 + 225 = 585 in.²

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A tank contains 1000 L of pure water. Brine that contains 0.05 kg of salt per liter of water enters the tank at a rate of 5 L/mi

Margaret [11]

Answer:

a) $y(t)=0.65\frac{Kg}{min}(tmin)$

b) $y(40)=26Kg$

Step-by-step explanation:

Data

Brine a (Ba)

$V_{Ba}=5\frac{Lt}{min}\\ Concentration(Bca)=0.05\frac{Kg}{Lt}$

Brine b (Bb)

$V_{Bb}=10\frac{Lt}{min}\\ Concentration(Bcb)=0.04\frac{Kg}{Lt}$

we have that per every minute the amount of solution that enters the tank is the same as the one that leaves the tank (15 Lt / min)

, then the amount of salt (y) left in the tank after (t) minutes: $y=V_{Ba}*B_{ca}+V_{Bb}*B_{cb}=5\frac{Lt}{min}*0.05\frac{Kg}{Lt}+10\frac{Lt}{min}*0.04\frac{Kg}{Lt}=\\0.25\frac{Kg}{min}+0.4\frac{Kg}{min}=0.65\frac{Kg}{min}$

Finally:

a) $y(t)=0.65\frac{Kg}{min}(tmin)$

b) $y(40)=0.65\frac{Kg}{min}(40min)=26Kg$

being y(t) the amount of salt (y) per unit of time (t)

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3 years ago

What is the slope of a line that contains the points (8-,4) and (10,-2)

erastova [34]

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} = \frac{-2 - (-4)}{10 - 8} = \frac{-2 + 4}{2} = \frac{2}{2} = 1$

   y - y₁ = m(x - x₁)
y - (-4) = 1(x - 8)
   y + 4 = 1(x) - 1(8)
   y + 4 = x - 8
       - 4    - 4
   y = x - 12

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3 years ago

Explain to me in words how you would find the slope of this line

vekshin1

Answer:

Step-by-step explanation:

go from one point to the other. From the left point to the right point you are running across (to the right) three times. Then you are ¨rising¨ (going down) once. going to the right is positive. If you are going down its negative. Vise versa. The formula is Rise/Run. your answer would be -1/3. the one is negative because it went down.Then divide it and you have -0.333. I hope I helped!

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3 years ago

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katovenus [111]

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3 years ago

Write the point-slope form of the equation of the line that passes through the points (-8, 2) and (1, -4).

Kruka [31]

So point-slope form is (y-y1) = m(x-x1). So first find m. m = (y2-y1) / (x2-x1) So for your problem m = (-4-2) / (1--8) = -6/9 = -2/3. Then plug the slope and a point into the point-slope equation so you can either get: y-2 = (-2/3)*(x+8) or y+4 = (-2/3)*(x-1). Both are valid.

Hope this helps!

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3 years ago