Question

What is the slope of a line that contains the points (8-,4) and (10,-2)

Answer 1

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} = \frac{-2 - (-4)}{10 - 8} = \frac{-2 + 4}{2} = \frac{2}{2} = 1$

   y - y₁ = m(x - x₁)
y - (-4) = 1(x - 8)
   y + 4 = 1(x) - 1(8)
   y + 4 = x - 8
       - 4       - 4
         y = x - 12