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3 years ago

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Help ASAP will give brainly 9th grade math

1 answer:

KatRina [158]3 years ago

8 0

<h2>Answer: </h2><h2>14. 2z + 3yz - 6z +2yz + y - z - 4y 2z - 6z -4z - z -5z + 3yz + 2yz + y - 4y 3yz + 2yz -5z + 5yz + y - 4y </h2><h2>Answer = -5z + 5yz - 3y </h2><h2 /><h2>15. -4ab + 3ax + ba - 6xa -4ab + ba Answer = -5ab - 3xa </h2><h2 /><h2>16. -c(3b - 7a) -3bc - 7ac Step-by-step explanation: </h2><h2>Hopes this helps. Mark as brainlest plz!</h2>

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Write an equation for the horizontal line that contains point E(-3, -1)

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Therefore, ur equation is : y = -1

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3 years ago

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Sveta_85 [38]

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3 years ago

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3 years ago

Read 2 more answers

PLEASE HELP!!! Write the equation of a line that goes through the point (6, 3) and is perpendicular to the line y = 4x + 1.

Tpy6a [65]

For this case we have that by definition, the equation of a line in the point-slope form is given by:

$y-y_ {0} = m (x-x_ {0})$

Where:

m: It is the slope of the line and $(x_ {0}, y_ {0})$ is a point through which the line passes.

We have the following equation of the slope-intersection form:

$y = 4x + 1$

Where the slope is $m = 4$

By definition, if two lines are perpendicular then the product of their slopes is -1.

Thus, a perpendicular line will have a slope:

$m_ {2} = \frac {-1} {m_ {1}}\\m_ {2} = \frac {-1} {4}\\m_ {2} = - \frac {1} {4}$

Thus, the equation will be of the form:

$y-y_ {0} = - \frac {1} {4} (x-x_ {0})$

Finally we substitute the given point and we have:

$y-3 = - \frac {1} {4} (x-6)$

Answer:

Option B

8 0

3 years ago