If the first number is x-1, since the numbers are consecutive, the second number will be x, the third number will be x+1 and the fourth number will be x+2.
(x-1) +(x) + (X+1) (X+2) = 354
4x + 2 =354
Therefore,
X = 88
Answer: The answer is the last option, Option D.
The equation of a sphere is:
(x – h)^2 + (y – k)^2 + (z – l)^2 = r^2
where h, k and l are the coordinates of the center of the
sphere
Using the midpoint formula, the coordinate of the center
is:
h = (-4 + 6) / 2 = 1
k = (7 + -5) / 2 = 1
l = (6 + 7) / 2 = 6.5
so the equation becomes:
(x – 1)^2 + (y – 1)^2 + (z - 6.5)^2 = r^2
we plug in any point, in this case point P to solve for r:
(-4 -1)^2 + (7 – 1)^2 + (6 - 6.5)^2 = r^2
r^2 = 61.25
So the full equation is:
<span>(x – 1)^2 + (y – 1)^2 + (z - 6.5)^2 = 61.25</span>
Answer:
67600000 possible licence plate numbers
Step-by-step explanation:
67600000 possible licence plate numbers
Number of choices for first letter of licence plate = 26
Number of choices for the second letter of license plate = 26
That is number of choices for the first two letters of the licence plate = 26×26 = 676
The number of choices for the first number of the licence plate = 10, also for the second there are 10 choices, the third 10, the fourth has 10 choices and the fifth has 10 choices
As such, the next 5 digits can be selected in 10 × 10 × 10 × 10 × 10 = 100000 different ways giving 100000 different numbers. Please not that this is the same as the number of numbers between 000000 and 100000 is 100000
When the two results are combined, it is observed that there are 676 × 100000 = 67600000 possible licence plate numbers