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3 years ago

Complete the steps to solve for x.

Mathematics

2 answers:

mylen [45]3 years ago

7 0

Answer: 11

Explanation:

(4/5)x - (1/4)x = 11
(16/20)x - (5/20)x = 11
(11/20)x = 11

NeTakaya3 years ago

3 0

The answer is 11 because 16-5/20 which is equal to 11/20.

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18 - 24i write in trigonometric form

stiks02 [169]

$\boxed{18-24i=30(cos(5.36)+isin(5.36))}$

<h2>Explanation:</h2>

Unlike 0, we can write any complex number in the trigonometric form:

$z=r(cos\alpha+isin\alpha)$

We have the complex number:

$18-24i$

So $r$ can be found as:

$r=\sqrt{x^2+y^2} \\ \\ \\ Where: \\ \\ x=18 \\ \\ y=-24 \\ \\ r=\sqrt{18^2+(-24)^2} \\ \\ r=\sqrt{324+576} \\ \\ r=\sqrt{900} \\ \\ r=30$

Now for α:

$\alpha=arctan(\frac{y}{x}) \\ \\ Since \ the \ complex \ number \ lies \ on \ the \ fourth \ quadrant: \\ \\ \alpha=arctan(\frac{-24}{18})=-53.13^{\circ} \ or \ 360-53.13=306.87^{\circ}$

Finally:

$Convert \ into \ radian: \\ \\ 360^{\circ}\times \frac{\pi}{180}=5.36rad \\ \\ \\ Hence: \\ \\ \boxed{18-24i=30(cos(5.36)+isin(5.36))}$

<h2>Learn more:</h2>

Complex conjugate: brainly.com/question/2137496

#LearnWithBrainly

6 0

4 years ago

One of the questions in the Pew Internet & American Life Project asked adults if they used the Internet, at least occasional

Marizza181 [45]

Answer:

Part (a) The point estimate of the proportion of adults aged 18 to 29 who use the Internet is 0.9498.

Part (b) The point estimate of the proportion of adults aged 30 to 49 who use the Internet is 0.8896.

Part (b) Estimate of the proportion of population who use the Internet is 0.7624.

Step-by-step explanation:

Consider the provided information.

Part (a) point estimate of the proportion of adults aged 18 – 29 who use the Internet

The results showed that 454 out of 478 adults aged 18-29 answered yes;

$\hat p=\frac{454}{478}=0.9498$

The point estimate of the proportion of adults aged 18 to 29 who use the Internet is 0.9498.

Part (b) Develop a point estimate of the proportion of adults aged 30-49

741 out of 833 adults aged 30-49 answered yes;

$\hat p=\frac{741}{833}=0.8896$

The point estimate of the proportion of adults aged 30 to 49 who use the Internet is 0.8896.

Part (c) Suppose your target population of interest is that of all adults (18 years of age and over). Develop an estimate of the proportion of that population who use the Internet.

$\hat p=\frac{454+741+1058}{478+833+1644}$

$\hat p=\frac{2253}{2955}=0.7624$

Estimate of the proportion of population who use the Internet is 0.7624.

7 0

3 years ago

Find the magnitude of the

sertanlavr [38]

17.49 is the magnitude of the resultant vector. This can be obtained by adding the vectors and finding magnitude.

<h3>Calculate the magnitude of the resultant vector:</h3>

Resultant vector: vector that gives the combined effect of all the vectors. When we add two or more vectors, the outcome is the resultant vector.

For example,

Sum of vector (3,4) and vector (5,7)

(3,4) + (5,7) = (3+5,4+7) = (8,11)

(8,11) is the resultant vector of vector (3,4) and vector (5,7)

Magnitude of a vector: the length of the vector. The magnitude of the vector a is denoted as ∥a∥.

Magnitude of a = (a₁, a₂)

∥a∥= $\sqrt{a_{1}^{2} +a_{2}^{2} }$

In the given question,

v (8,10) and w (7, -1)

Adding the vectors,

resultant vector = (8,10) + (7, -1) = (15, 9)

Magnitude of a vector (a,b) = √a²+b²

Here, magnitude = √15²+9² = √225+81 = √306 ≈ 17.49

Hence 17.49 is the magnitude of the resultant vector.

Learn more about vectors:

brainly.com/question/27870005

#SPJ1

7 0

2 years ago

A box is to be made out of a 8 cm by 20 cm piece of cardboard. Squares of side length x cm will be cut out of each corner, and t

abruzzese [7]

Answer:

hi! im sorry if this is wrong, im gonna try my hardest.

V= 160

L= 240

W=34

sry this is prob wrong just wanted to help ;(

7 0

3 years ago

I Need to know a or b is the answer to this question

grandymaker [24]

Answer:

Step-by-step explanation:

in option B, you are adding the 3 pound plastic box to each cardboard box

in option A, you have 5 separate carboard packages, and one 3 pound plastic box

This [option a] is the diagram that matches the scenario given.

Think of the x's as normal numbers. Let's say the weight of each "x" is 1. [it's not I'm aware that this question is different]

if you have 5 x's, you have

1 1 1 1 1 3

<em>not </em>1+3 ; 1+3 ; 1+3 ; 1+3 ; 1+3

you would only have this if you were to add a 3 pound plastic box to each individual package

3 0

2 years ago