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3 years ago

2Al (s) + 3Cl2 (g) --> 2AlCl3 (s) (balanced)

Chemistry

1 answer:

Triss [41]3 years ago

3 0

Answer:

Percent yield = 65.2 %

Explanation:

The reaction determines this:

2 moles of Al react to 3 moles of chlorine gas in order to produce 2 mol of aluminum chloride.

We determine the moles of chlorine:

52 g . 1mol /70.9g = 0.733 moles of Cl₂

3 moles of gas can produce 2 moles of salt

Then, our 0.733 moles may produce (0.733 . 2) / 3 = 0.489 moles of AlCl₃

We convert moles to mass to predict the 100 % yield

0.489 mol . 133.3 g /mol = 65.19 g

Percent yield = (Yield produced / 100 % yield) . 100

Percent yield = (42.5 g / 65.19g) . 100 = 65.2 %

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30 points please helppp

Pavel [41]

Answer:

λ = 4.59 ×10⁻³ nm

Explanation:

Given data:

Energy of light = 4.33 ×10⁻¹⁴ J

Wavelength of light = ?

h = 6.626×10⁻³⁴ js

c = 3×10⁸ m/s

Solution:

Formula:

E = hc/λ

4.33 ×10⁻¹⁴ J = 6.626×10⁻³⁴ Js× 3×10⁸ m/s / λ

λ = 6.626×10⁻³⁴ Js× 3×10⁸ m/s / 4.33 ×10⁻¹⁴ J

λ = 19.878 ×10⁻²⁶ Jm / 4.33 ×10⁻¹⁴ J

λ = 4.59 ×10⁻¹² m

λ = 4.59 ×10⁻³ nm

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3 years ago

Evaluate - if you put a scale in an elevator and weigh yourself as you ascend and the descend, does the scale have the same read

N76 [4]

No, when ascending, you would weigh more, and when you descend, you weigh less.

This is due to the difference in the effect of gravity.

4 0

3 years ago

Read 2 more answers

0.378g grams of a compound is made up of 0.273g of Mg and 0.105g nitrogen. Find its empirical formula.

Harrizon [31]

Answer:

The empirical formula of the compound is $Mg_3N_2$ .

Explanation:

Mass of magnesium in compound = 0.273 g

Mass of nitrogen in the compound = 0.105 g

Moles of magnesium = $\frac{0.273 g}{24.305 g/mol}=0.0112 mol$

Moles of nitrogen = $\frac{0.105 g}{14.0067 g/mol}=0.00750 mol$

Form empirical formula divides the lowest value of moles of an element present with all the moles of elements present.

Magnesium $=\frac{0.0112 mol}{0.00750 mol}=1.5$

Nitrogen $=\frac{0.00750mol}{0.00750 mol}=1$

The empirical formula of a compound:

$Mg_{1.5}N_1=Mg_{\frac{15}{10}}N_1=Mg_{15}N_{10}=Mg_3N_2$

The empirical formula of the compound is $Mg_3N_2$ .

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g For each of the following cases, indicate whether the first entity is greater than, less than or equal to the second entity. W

Marianna [84]

Answer:

Explanation

check the solution in the attached

7 0

3 years ago

Balance the equation Ag2O ->Ag + O2

UNO [17]

Answer:

For balancing this equation 

we need to put

Ag2O. = 2 

Ag = 4 

O2 = 1 

Hope it will help

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3 years ago