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belka [17]
3 years ago
14

octyl methoxycinnamate and oxybenzone are common ingredients in sunscreen applications. These compounds work by absorbing uv b l

ight (wavelength 280-320 nm), the UV light most associated with sunburn symptoms. What frequency range of light do these compounds absorb?
Chemistry
1 answer:
Rus_ich [418]3 years ago
4 0

Answer:

0.94 PHz – 1.1 PHz

Explanation:

Case 1. <em>280 nm </em>

The formula relating the frequency (f) and wavelength (λ) is

fλ = c                                         Divide both sides by f.

f = c/λ

c = 2.998 × 10⁸ m·s⁻¹

λ = 280 nm = 280 × 10⁻⁹ m     Calculate f.

f = 2.998 × 10⁸/280 × 10⁻⁹

f = 1.1 × 10¹⁵ s⁻¹ = 1.1 PHz

===============

Case 2. 320 nm

λ = 320 nm = 320 × 10⁻⁹ m     Calculate f.

f = 2.998 × 10⁸/320 × 10⁻⁹

f = 9.4 × 10¹⁴ s⁻¹ = 0.94 × 10¹⁵ s⁻¹ = 0.94 PHz

The frequency range is 0.94 PHz to 1.1 PHz.

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How many atoms make up a diatomic molecule?
zalisa [80]
The prefix 'di' means two. Hence two atoms make up a diatomic molecule.
Hope this helps!
6 0
3 years ago
Amobarbital sodium react with ethanolic sodium hyrooxide
CaHeK987 [17]

Amobarbital (like all barbiturates) works by being incontestible to the GABAA receptor at either the alpha or the beta subunit.

<h3>What is the mechanism of amobarbital?</h3>

Amobarbital (like all barbiturates) works by binding to the GABAA receptor at either the alpha or the beta subunit. These are compulsory sites that are distinct from GABA itself and also distinct from the benzodiazepine binding site.

Amobarbital is a barbiturate classified as having a halfway duration of action, meaning that the effects of the drug can last from 4-6 amobarbital increases the effects of benazepril by apparatus: pharmacodynamic synergism.

So we can conclude that Amobarbital, 5-ethyl-5-isoamyl barbituric acid like all barbiturates.

Learn more about Amobarbital here: brainly.com/question/7237163

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6 0
2 years ago
What is the molarity (M) of the following solutions?
Dennis_Churaev [7]

Answer:

The molarity (M) of the following solutions are :

A. M = 0.88 M

B. M = 0.76 M

Explanation:

A. Molarity (M) of 19.2 g of Al(OH)3 dissolved in water to make 280 mL of solution.

Molar mass of Al(OH)3 = Mass of Al + 3(mass of O + mass of H)

                                      = 27 + 3(16 + 1)

                                      = 27 + 3(17) = 27 + 51

                                      = 78 g/mole

Al(OH)_3 = 78 g/mole

Given mass= 19.2 g/mole

Mole = \frac{Given\ mass}{Molar\ mass}

Mole = \frac{19.2}{78}

Moles = 0.246

Molarity = \frac{Moles\ of\ solute}{Volume\ of\ solution(L)}

Volume = 280 mL = 0.280 L

Molarity = \frac{0.246}{0.280)}

Molarity  = 0.879 M

Molarity  = 0.88 M

B .The molarity (M) of a 2.6 L solution made with 235.9 g of KBr​

Molar mass of KBr = 119 g/mole

Given mass = 235.9 g

Mole = \frac{235.9}{119}

Moles = 1.98

Volume = 2.6 L

Molarity = \frac{Moles\ of\ solute}{Volume\ of\ solution(L)}

Molarity = \frac{1.98}{2.6)}

Molarity = 0.762 M

Molarity = 0.76 M

4 0
3 years ago
How many grams of tris (mw 121.1) would you need to prepare 100 ml of a 100 mm tris solution? _________ grams?
Tems11 [23]

Molarity = (Mass/ molar mass) x (1/ volume of solution in Litres)

Mass = Molarity x molar mass x  volume of solution in Litres

Molarity of Tris = 100 mM = 0.1 M

volume of Tris sol. = 100 mL = 0.1 L

molar mass of Tris = 121.1 g/mol

Hence,

mass of Tris = Molarity of Tris x molar mass ofTris x volume of Tris solution

= 0.1 M x 121.1 g/mol x 0.1 L

= 1.211 g

mass of Tris = 1.211 g


7 0
4 years ago
Which of the four containers represents a compound?<br> A) Cl <br> B) H2O <br> C) N2 <br> D) Na
MissTica
B)H20 Hydrogen+oxygen=H2O
(Water) you should know this
6 0
3 years ago
Read 2 more answers
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