Answer:
C= 0.532M
Explanation:
The equation of reaction is
H2SO4 + 2KOH = K2SO4+ H2O
nA= 1, nB= 2, CA= ?, VA= 48.9ml, CB= 1.5M, VB= 34.7ml
Applying
CAVA/CBVB = nA/nB
(CA× 48.9)/(1.5×34.7)= 1/2
Simplify
CA= 0.532M
N -3
Ba +2
Sr +2
F -1
I -1
Ca +2
Mg +2
S -2
S -2
Al +3
//
Ba3N2
SrF2
CaI2
MgS
Al2S3
//
I don't really understand 2.
Carbon-14 is a radioactive isotope used to date organic material. Its consistent rate of decay allows the age of an object to be determined by the proportion of carbon-14 to other carbon isotopes. This process is called radiocarbon dating. Carbon-14 is also used as a radioactive tracer for medical tests.
Full question:
The IUPAC name for CH3CH2C≡CCH3 is:
Answer:
2-pentyne
Explanation:
To name hydrocarbons, you first you have to identify the longest carbon chain. There are 5 carbons in this chain, so we know the name is "pent".
You then have to identify the presence of any double or triple bonds. If double bonds, it is an alkene, if triple bonds, it is an alkyne. In this case there is a triple bond, so we know the hydrocarbon is pentyne.
You then number the chain to give the lowest number to the triple bond. It could either be 4 (countnig carbons from left to right) or 2 (from right to left). Therefore, the answer is 2-pentyne.
