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LuckyWell [14K]
3 years ago
6

What is the molarity of a solution containing 17.0 g of KCl in 213 mL of KCl solution?

Chemistry
1 answer:
Anarel [89]3 years ago
5 0

Answer:

1.070MKCl

Explanation:

So we know that the original formula is M= n/L (n being moles of solute, L being liters of solvent)

Since we do not have liters in this problem, we would need to convert  milliliters to liters

<u>213 mL= 0.213 L</u>

We then see that we do not have moles, but we do have a mass, being <u>17.0 g.</u> we would need to convert these grams to moles, giving us <u>0.228 mol.</u>

Then, you would plug in <u>0.228 for your n</u>, and now you are ready to solve your original formula, plugging everything in.

M=n/L

M=0.228 mol/0.213L

M= 1.070MKCl

I know this was long, but I hope this helps (:

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Explanation:

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4 0
3 years ago
Acetone (nail polish remover) has a density of 0.7857 g &gt;cm3.
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If acetone has a density of 0.7857 \frac{g}{cm^{3} }  the mass in grams of point A is 22.4 g and the volume at point B is 8.32 mL.

<h3>What is acetone?</h3>

Acetone is known as a chemical substance that is usually found in the environment but can also be produced artificially. Acetone is a polar organic product that interacts very well with water molecules, generating dipole-dipole relationships.It is colorless with a distinctive smell and taste, we find it in products known as <u>cleaning and personal care products</u>, but we can also use it as a solvent for substances.

Also in the environment in <u>plants, trees and in volcano emissions or in forest fires</u>, it does not become <em>toxic</em> in low doses but if it is exposed to an individual in high doses it can become <em>fatal</em>.

In the statement we can find that acetone has a density of 0.7857 \frac{g}{cm^{3} }.

Therefore, we can confirm that if acetone has a density of 0.7857 \frac{g}{cm^{3} }  the mass in grams of point A is 22.4 g and the volume at point B is 8.32 mL.

To learn more about acetone visit: brainly.com/question/13334667?referrer=searchResults

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7 0
2 years ago
A 0.529-g sample of gas occupies 125 ml at 60. cm of hg and 25°c. what is the molar mass of the gas?
Llana [10]

<span>Let's </span>assume that the gas has ideal gas behavior. <span>
Then we can use ideal gas formula,
PV = nRT<span>

</span><span>Where, P is the pressure of the gas (Pa), V is the volume of the gas (m³), n is the number of moles of gas (mol), R is the universal gas constant ( 8.314 J mol</span></span>⁻¹ K⁻¹) and T is temperature in Kelvin.<span>
<span>
</span>P = 60 cm Hg = 79993.4 Pa
V = </span>125  mL = 125 x 10⁻⁶ m³

n = ?

<span> R = 8.314 J mol</span>⁻¹ K⁻¹<span>
T = 25 °C = 298 K
<span>
By substitution,
</span></span>79993.4 Pa<span> x </span>125 x 10⁻⁶ m³ = n x 8.314 J mol⁻¹ K⁻¹ x 298 K<span>
                                          n = 4.0359 x 10</span>⁻³ mol

<span>
Hence, moles of the gas</span> = 4.0359 x 10⁻³ mol<span>

Moles = mass / molar mass

</span>Mass of the gas  = 0.529 g 

<span>Molar mass of the gas</span> = mass / number of moles<span>
                                    = </span>0.529 g / 4.0359 x 10⁻³ mol<span>
<span>                                    = </span>131.07 g mol</span>⁻¹<span>

Hence, the molar mass of the given gas is </span>131.07 g mol⁻¹

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otez555 [7]

Answer:

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Explanation:

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