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LuckyWell [14K]
3 years ago
6

What is the molarity of a solution containing 17.0 g of KCl in 213 mL of KCl solution?

Chemistry
1 answer:
Anarel [89]3 years ago
5 0

Answer:

1.070MKCl

Explanation:

So we know that the original formula is M= n/L (n being moles of solute, L being liters of solvent)

Since we do not have liters in this problem, we would need to convert  milliliters to liters

<u>213 mL= 0.213 L</u>

We then see that we do not have moles, but we do have a mass, being <u>17.0 g.</u> we would need to convert these grams to moles, giving us <u>0.228 mol.</u>

Then, you would plug in <u>0.228 for your n</u>, and now you are ready to solve your original formula, plugging everything in.

M=n/L

M=0.228 mol/0.213L

M= 1.070MKCl

I know this was long, but I hope this helps (:

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