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Vitek1552 [10]
3 years ago
7

Which one of the ff is correct about Acids?

Chemistry
1 answer:
Rashid [163]3 years ago
8 0

Answer:

b acid have ph less than 7

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Approximately how much greater in mass is a d2o molecule than an h2o molecule? (assume the oxygen atoms have a mass number of 16
faust18 [17]

The deuteriuoted water that is D_{2}O consists of an isotope of hydrogen in place of hydrogen from the normal water. The approximate mass of deuteriuoted water and normal water can be calculated as {(2×2)+16} = 20. However the exact mass of D_{2}O is 20.027 g/mole, whereas the mass of water can also be calculated as- {(1×2)+16}=18, however the exact mass of (H_{2}O) molecule is 18.015 g/mole. Thus the difference between the mass of the molecules are (20.027 - 18.015) = 2.01 2g/mole.

6 0
4 years ago
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Which statement is true? A reaction in which the entropy of the system decreases can be spontaneous only if it is exothermic. A
victus00 [196]

Answer:

A reaction in which the entropy of the system decreases can be spontaneous only if it is exothermic.

Explanation:

The spontaneity of a reaction depends on the Gibbs free energy(ΔG).

  • If ΔG < 0, the reaction is spontaneous.
  • If ΔG > 0, the reaction is nonspontaneous.

ΔG is related to the enthalpy (ΔH) and the entropy (ΔS) through the following expression:

ΔG = ΔH - T.ΔS

where,

T is the absolute temperature (always positive)

Regarding the exchange of heat:

  • If ΔH < 0, the reaction is exothermic.
  • If ΔH > 0, the reaction is endothermic.

<em>Which statement is true? </em>

<em>A reaction in which the entropy of the system decreases can be spontaneous only if it is exothermic. </em>TRUE. If ΔS < 0, the term -T.ΔS > 0. ΔG can be negative only if ΔH is negative.

<em>A reaction in which the entropy of the system increases can be spontaneous only if it is endothermic.</em> FALSE. If ΔS > 0, the term -T.ΔS < 0. ΔG can be negative if ΔH is negative.

<em>A reaction in which the entropy of the system decreases can be spontaneous only if it is endothermic.</em> FALSE. If ΔS < 0, the term -T.ΔS > 0. ΔG cannot be negative if ΔH is positive.

<em>A reaction in which the entropy of the system increases can be spontaneous only if it is exothermic.</em> FALSE. If ΔS > 0, the term -T.ΔS < 0. ΔG can be negative even if ΔH is positive, as long as |T.ΔS| > |ΔH|.

6 0
3 years ago
A 4.00 M H3PO4 solution will contain ___ g of H3PO4 in 0.500 L of solution.
harkovskaia [24]
Which of the following statements is generally true about change in the workplace ? a ) Most people accept change easily . b) Smart companies can avoid change altogether. c) Change in the workplace fairly infrequently d) Individuals can learn to manage the change in their lives.
5 0
3 years ago
Why does organic chemistry have a wide variety from compounds primarily based on only two elements? please help
andreev551 [17]

Answer:

Explanation:  Organic chemistry have a wide variety from compounds of the presence of two elements namely

  • Carbon
  • Hydrogen

 Organic molecules comprises of multiple chains of carbon atoms with different  lengths and because of the ability of carbon to bond with many elements, This produces  a variety of compounds which no other atom or element can. The main variety of compounds exists in the combination of carbon and hydrogen forming hydrocarbons which are virtuall everywhere around us

4 0
3 years ago
The solubility of N2in blood at 37°C and at a partial pressure of 0.80 atm is 5.6 × 10−4mol/L. A deep-sea diver breathes compres
Luda [366]

Solution :

According to Henry's law of solubility, we have c = kp

Henry's law constant, $k=\frac{c}{p}$

                                      $=\frac{0.00056}{0.80}$

                                      = 0.0007 mol/L.atm

When the pressure is = 4 atm

The solubility is c = 0.0007 mol/(L.atm) x 4 atm

                             = 0.0028 mol/L

Therefore, in a 5 liter of blood, the moles of nitrogen dissolved

= 0.0028 x 5

= 0.014 moles

At the surface, the solubility is = 0.00056 mol/L

So the moles of the nitrogen dissolved = 5 x 0.00056

                                                                  = 0.0028 moles

Therefore, the number of moles of nitrogen released = 0.014 - 0.0028

                                                                                         = 0.0112 moles

Given total pressure = 1 atm                                                                        

Temperature = 37 degree C

                     = 37 + 273

                      = 310 K

R = $0.0821\ L -atm/ mol.K $

Therefore, volume of the nitrogen is

$V=\frac{nRT}{P}$

$V=\frac{0.0112 \times 0.0821 \times 310}{1}$

  = 0.285 L

5 0
3 years ago
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