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NikAS [45]
2 years ago
8

The function h(t)=-16t^2+75t+80 models the height in feet, h, of a ball as it is thrown into the

Mathematics
1 answer:
sukhopar [10]2 years ago
6 0

Answer:

t = 4\\

or

t=0.6875

Step-by-step explanation:

124 = -16t^2+75t+80\\-16t^2+75t-44=0

Solving for t using the quadratic formula we get:

t = 4\\

or

t=0.6875

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Please Help !!!
Rina8888 [55]

Answer:

40

Step-by-step explanation:

Sums:

1, 3

2, 2

4, 0

31 and 22 are to small of numbers.  That leaves 40.

40 and 04

so 40

  - 04

____

=  36

Good luck,

Camryn :)

7 0
3 years ago
Please help! What is the line's slope??
MariettaO [177]
The slope is the rise over run. Basically, any line has a constant increase. If you are looking at a line on a graph and each point it meets at is 1 up and 1 over, the slope is 1. Say the line goes up two and over one for each time it meets an actual point, the slope would be 2. If it is 1 up and 2 over, it would be 1/2.
4 0
2 years ago
Jenny has saved $3,800 over the last 12 months. She saved either $250 or $350 a month. During the 12 month period, how many time
Nana76 [90]

Answer:

Jenny save 4 times \$ 250 for the month

Step-by-step explanation:

Given Jenny has saved \$3,800 over the last 12 months.

She saved either \$250 or \$350 a month.

Let the number of months to save \$250 be x

Let the number of months to save \$350 be y

Total period is 12 month.

x+y=12 \ \ \ \ equation\ 1

Jenny has saved $3,800 over the last 12 months.

250x+350y=3800

Dividing both side from 50 we get,

\frac{250}{50}x+\frac{350}{50}y= \frac{3800}{50}

5x+7y=76 \ \ \ \ equation\ 2

Now Multiplying  equation 1 by 5 we get,

5\times(x+y)=5\times 12\\5x+5y=60\ \ \ \ equation \ 3

Now Subtracting Equation 3 by equation 2 we get,

(5x+7y=76)-(5x+5y=60)\\2y=16\\y=\frac{16}{2}= 8

Substituting the value of y in equation 1 we get,

x+y=12\\x+8=12\\x=12-8\\x=4

∴ Jenny save 4 Months of  \$ 250 and 8 Months of  \$ 350in a 12 month duration

4 0
3 years ago
Read 2 more answers
I need help? Can anyone help me ?
Rina8888 [55]
Given a coordinate point (x, y), the first value of the point represents the value on the x-axis while the second value represent the value on the y-axis.

1.) To express the values (-4, -1), (-1, 2), (1, -4), (2, -3), (4, 3) as a table, we have:

 x          y
-4         -1
-1          2
 1         -4
 2         -3
 4          3

The values (-4, -1), (-1, 2), (1, -4), (2, -3), (4, 3) expressed as a graph have been attached as graph_1


To express the values (-4, -1), (-1, 2), (1, -4), (2, -3), (4, 3) as a mapping, we have two circles with one labelled x and the other one labelled y.
Inside the circle labelled x are the numbers -4, -1, 1, 2, 4 written vertically and inside the circle labelled y are the numbers -4, -3, -1, 2, 3 written vertically.
There are lines joining from the circle labelled x to the circle labelled y with line joining -4 in circle x to -1 in circle y, -1 in circle x to 2 in circle y, 1 in circle x to -4 in circle y, 2 in circle x to -3 in circle y, 4 in circle x to  3 in circle y.

The domain of the relation is the set of the x-values of the relation, i.e. domain is {-4, -1, 1, 2, 4}.
The range of the relation is the set of the y-values of the relation, i.e. range is {-4, -3, -1, 2, 3}

2.) To express the values (-2, 1), (-1, 0), (1, 2), (2, -4), (4, 3) as a table, we have:

 x          y
-2         1
-1         0
 1          2
 2         -4
 4          3

The values (-2, 1), (-1, 0), (1, 2), (2, -4), (4, 3) expressed as a graph have been attached as graph_2


To express the values (-2, 1), (-1, 0), (1, 2), (2, -4), (4, 3) as a mapping, we have two circles with one labelled x and the other one labelled y.
Inside the circle labelled x are the numbers -2, -1, 1, 2, 4 written vertically and inside the circle labelled y are the numbers -4, 0, 1, 2, 3 written vertically.
There are lines joining from the circle labelled x to the circle labelled y with a line joining -2 in circle x to 1 in circle y, -1 in circle x to 0 in circle y, 1 in circle x to 2 in circle y, 2 in circle x to -4 in circle y, 4 in circle x to  3 in circle y.

The domain of the relation is the set of the x-values of the relation, i.e. domain is {-2, -1, 1, 2, 4}.
The range of the relation is the set of the y-values of the relation, i.e. range is {-4, 0, 1, 2, 3}
7 0
3 years ago
Charles is going campin with his family. His campsites 7/8 miles away. They walk at a steady speed of 1 1/2 mi/hr. How many minu
Elena L [17]
x-\ travel\ in\ minutes\\\\From\ proportion:\\\\1.5\ \ \ \ -\ \ \ \ 60\\\frac{7}{8}\ \ \  \ \ \ -\ \ \ \ x\\\\1.5x=60\cdot\frac{7}{8}\\\\1.5x=\frac{420}{8}\\\\1.5x=\frac{105}{2}\\\\1.5x=52.5\ \ \ \ \ |:1.5\\\\x=35\ minutes
5 0
3 years ago
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