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3 years ago

2x + 3 + 4x + 8 = 3x - 10

Mathematics

1 answer:

vodomira [7]3 years ago

8 0

$\text {Hello! Let's solve this Equation!}$

$\text {Your First Step is to Simplify the Equation:}$

$\text {(2x+4x)+(8+3)}$

$\text {6x+11=3x-10}$

$\text {The Next Step is to Subtract 3x:}$

$\text {6x+11-3x=3x-10-3x}\\\text {3x+11=-10}$

$\text {Next Step is to Subtract 11:}$

$\text {Q: Why Subtract 11?}$

$\text {A: So they cancel out. We cross them out once we subtract.}$

$\text {3x+11-11=-10-11}\\\text {3x=-21}$

$\text {The Final Step is to Divide 3:}$

$\text {3x/3=-21/3}$

$\text {Your Answer will be}$

$\fbox {x=-7}$

$\text {Best of Luck!}$

$\text {-LimitedX}$

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The Baldwin family walked of a mile in of an hour. What is their unit rate in miles per hour? (5 points)

Lisa [10]

So walked 4/5 mile in a 4/9 h so just use the rule of 3 simple

60 minutes ------ 1 hour
x min. ----------- 4/9 h
--------------------------------
x = 4/9 *60/1 = 240/9 = 26,6 min.

4/5 mile -------in 26,6 min.
1 mile -------- x min.
-----------------------------
x = 1*26,6/(4/5) = 26,6 /(0,8) = 33,25 min.

1 mile ..... 33,25 min.
x miles ----- 60 min.
---------------------------
x = 60/33,25 = 1,8 miles

so their unit rate in miles per hour will be 1,8 miles / hour

hope this will help you.

3 0

3 years ago

Evaluate \dfrac{3}{2}+(-k)+(-2)

Dimas [21]

As I understand, we need to evaluate the given rational expression, we will get that the evaluated expression is equal to - 1/10

<h3>Evaluating expressions:</h3>

Evaluating an expression just means that we need to replace the variable in the expression for a given value, here we have the expression:

$\frac{3}{2} + (-k) + (-2)$

And we want to evaluate it in:

$k = -\frac{2}{5}$

So we just need to replace k by that value in the above expression, we will get:

$\frac{3}{2} + (-(-\frac{2}{5} )) + (-2)$

Now we can just solve this:

$\frac{3}{2} + (-(-\frac{2}{5} )) + (-2)\\\\\frac{3}{2} + \frac{2}{5} + (-2)\\\\\frac{15}{10} + \frac{4}{10} + (-2) = \frac{19}{10} - \frac{20}{10}= -\frac{1}{10}$