What are the roots of x cubed - 7*x squared + 13x-6

Mathematics

1 answer:

Natalka [10]2 years ago

5 0

The roots of x^3 - 7x^2 + 13x - 6 are 0.697, 2 and 4.303

<h3>How to determine the roots?</h3>

The expression is given as:

x^3 - 7x^2 + 13x - 6

Express as a function

f(x) = x^3 - 7x^2 + 13x - 6

Next, we plot the graph of the function f(x) (see attachment)

From the attached graph, we have the zeros to be:

x = 0.697, 2 and 4.303

Hence, the roots of x^3 - 7x^2 + 13x - 6 are 0.697, 2 and 4.303

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The shear strength of each of ten test spot welds is determined, yielding the following data (psi).

Mumz [18]

Answer:

a) Mean = 382.3 psi

Standard deviation = 20.8 psi

b) 392.7 psi

c) P(X<400)=0.8026

Step-by-step explanation:

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$M=\frac{1}{n}\sum x_i=\frac{1}{10}(389+405+409+367+358+415+376+375+367+362)\\\\M=\frac{1}{10}(3823)=382.3\\\\\mu\approx M=382.3$

$s=\sqrt{\frac{1}{n-1}\sum (x_i-M)^2}=\sqrt{\frac{1}{10-1}(389-382.3)^2+...+(362-383.2)^2}\\\\\\s=\sqrt{\frac{1}{9}(3906.1)}=\sqrt{434}=20.8\\\\\\\sigma\approx s=20.8$