3.5 (E) - 6.7 (B)+ 8 (t)= 18.2
No they are not quivalent
Answer:
((2 x^2 + 1)^2)/(x^2)
Step-by-step explanation:
Simplify the following:
(2 x + 1/x)^2
Hint: | Put the fractions in 2 x + 1/x over a common denominator.
Put each term in 2 x + 1/x over the common denominator x: 2 x + 1/x = (2 x^2)/x + 1/x:
((2 x^2)/x + 1/x)^2
Hint: | Combine (2 x^2)/x + 1/x into a single fraction.
(2 x^2)/x + 1/x = (2 x^2 + 1)/x:
((2 x^2 + 1)/x)^2
Hint: | Distribute exponents over quotients in ((2 x^2 + 1)/x)^2.
Multiply each exponent in (2 x^2 + 1)/x by 2:
Answer: ((2 x^2 + 1)^2)/(x^2)
RemarkThis is costing you an awful lot of points, but it is a little hard to read. If I'm not interpreting it correctly, leave some sort of note below my answer.
Question OneIn the first question you want a line that is parallel to x = 4 and goes through the point (-7,3). If I'm reading this correctly then the line you want is x = -7. You only need the x value of the given point. I'll put a graph there to show you what it looks like on a grid. The graph is the left one for this question.
Question TwoHere I think you want the line going through (5,-1) and perpendicular to y = 4x - 7. I will make a graph for that one as well.
Begin with the slopeTwo lines are perpendicular to each other if their slopes multiply to - 1
Given slope (m1) = 4
perpendicular slope = m2
Formulam1 * m2 = - 1
4 * m2 = -1 Divide by 4
m2 = -1/4
So far what you have is
y = (-1/4)x + b
Now use the given point to solve for b
x = 5
y = - 1
b = ??
-1 = (-1/4)*5 + b
-1 = -5/4 + b Add 5/4 to both sides
-1 + 5/4 + b Make -1 into -4/4
b = -4/4 + 5/4
b = (-4 + 5)/4
b = 1/4
So the line that you want is
y = (-1/4) x + 1/4
AnswersOne: x = - 7
Two: y = (-1/4)x + 1/4
NoteThe right graph is of y = 4x - 7 and y = (-1/4)x + 1/4
Answer:
positive
Step-by-step explanation:
If the variables tend to increase and decrease together, the association is positive.
hope this helps :)