Question

Below, the two-way table is given for a class of students. Juniors Seniors Free Freshmen Sophomore Male 4 6 2 2. Female 3 4 6 3 Total If a student is selected at random, find the probability the student is a junior given that it's male. Round to the nearest whole percent.​

Answer 1

Answer:

$Pr = 7\%$

Step-by-step explanation:

Given

See attachment for graph

Required

Find P(Junior|Male)

To do this, we first calculate the total students.

$Total = 4 + 6 + 2 + 2 + 3 + 4 + 6 + 3$

$Total = 30$

Next, select the value in the cell that intersects Male and Junior

$Male\ and\ Junior = 2$

Hence, the probability is

$Pr = \frac{Male\ and\ Junior}{Total}$

$Pr = \frac{2}{30}$

$Pr = 0.067$

Express as percentage

$Pr = 0.067*100\%$

$Pr = 6.7\%$

Approximate

$Pr = 7\%$

Answer 2

Answer:

14%

Step-by-step explanation:

2(junior males) out of 14 (the total of males) is 14.29%, which is rounded to a whole percent of 14%. Hope this helps!

p.s. (I was on the same problem on acellus and figured it out. It took forever though)