![\bf \textit{sum of all interior angles in a polygon}\\\\ S=180(n-2)~~ \begin{cases} n=\textit{number of sides}\\[-0.5em] \hrulefill\\ n=8 \end{cases}\implies S=180(8-2) \\\\\\ S=180(6)\implies S=1080](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bsum%20of%20all%20interior%20angles%20in%20a%20polygon%7D%5C%5C%5C%5C%20S%3D180%28n-2%29~~%20%5Cbegin%7Bcases%7D%20n%3D%5Ctextit%7Bnumber%20of%20sides%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20n%3D8%20%5Cend%7Bcases%7D%5Cimplies%20S%3D180%288-2%29%20%5C%5C%5C%5C%5C%5C%20S%3D180%286%29%5Cimplies%20S%3D1080)
now, we know 7 of those angles are already 835°, so the last one must be 1080 - 835 = 245°.
Answer:
40 Yd^2
Step-by-step explanation:
Take out the 7 from that problem and multiply the regular shape so whats 8 times 5?
Question 1:
Slope = 1/5
y = mx + c
y = 1/5 x + c
at point (5, -1)
-1 = 1/5 (5) + c
- 1= 1 + c
c = - 2
y = 1/5x - 2
5y = x - 10
Question 2:
slope = (9-5)/(3-1)
Slope = 2
y = mx + c
y = 2x + c
at point (1, 5)
5 = 2(1) + c
c = 5 - 2
c = 3
y = 2x + 3
Answer: 11 = y ÷ 6
Step-by-step explanation: since the problem says 11 is that means the equation equals 11 and when it says quotient that means that the equation must include division.
