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Nitella [24]
3 years ago
5

Which table represents a nonlinear function?

Mathematics
2 answers:
Leno4ka [110]3 years ago
8 0
I think it the first one
aleksley [76]3 years ago
6 0
The top left table represents a non linear function
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X^2+5x=3x+11 solve by completing the square
goldenfox [79]
X^2+2x-11=0, this would be the answer that you are looking for m8.
7 0
3 years ago
PLZ HELP I NEED THISS
Nikolay [14]

Answer:

Step-by-step explanation:

1) 5

2) -3, which becomes 3

3) it would land at either 3, or -3

4) 7 or -7

5) if it is to the left, that means it is negative. there fore, your answer is -4

6 0
2 years ago
Enter the range of data 37,45,20,34,28,80
Montano1993 [528]

Answer:

60

Step-by-step explanation:

To find the range, you subtract the largest number and the smallest number.

Largest number: 80

Smallest number: 20

80-20=60

8 0
3 years ago
Read 2 more answers
Assume the equation has a solution for z.<br> -cz+ 6z = tz + 83<br>z=?​
solong [7]

Answer:

z = 83 / (- c + 6 - t)

Step-by-step explanation:

Given:

-cz+ 6z = tz + 83

z=?​

-cz+ 6z = tz + 83

Collect like terms

-cz+ 6z - tz = 83

Factorize

z(- c + 6 - t) = 83

Divide both sides by (- c + 6 - t)

z(- c + 6 - t) / (- c + 6 - t) = 83 / (- c + 6 - t)

z = 83 / (- c + 6 - t)

5 0
2 years ago
(cosxtanx-tanx+2cosx-2)/tanx+2=cosx-1<br> can someone show me how to prove this?
uysha [10]

Answer:

See detail below.

Step-by-step explanation:

A word of caution before getting to the actual problem: I believe there is an important set of brackets missing in the original post. The expression on the left hand side should be:

(cosxtanx-tanx+2cosx-2)/(tanx+2)

Without the brackets, it is left unclear whether the denominator is just tanx or tanx+2. I recommend to use brackets wherever any doubt could arise.

Now to the actual problem: \we can make the following transformations on the left hand side:

\frac{\cos x \tan x + 2\cos x -2}{\tan x +2}=\frac{\cos x \frac{\sin x}{\cos x}  + 2\cos x -2}{\frac{\sin x +2\sin x}{\cos x} }=\\=\frac{\cos x \sin x - \sin x + 2\cos^2 x - 2\cos x}{\sin x + 2\cos x}=\\=\frac{\cos x \sin x +2\cos^2 x }{\sin x + 2\cos x}-1=\\=\cos x -1

which is shown to be the same as the right hand side, which was to be shown.

7 0
3 years ago
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