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nikitadnepr [17]
3 years ago
8

help me!!! A polynomial that has 4 turning points is multiplied by another polynomial that has 1 zeros. What is the minimum degr

ee of the new polynomial?
Mathematics
1 answer:
Anna71 [15]3 years ago
7 0
The polynomial with 4 turning points has the degree of 4+1 = 5. Whatever number of turning points there are, add 1 and you get the degree.

The degree of the polynomial with one root or zero is 1

When you multiply polynomials, the degrees will add so 5+1 = 6 is the minimum degree of the new polynomial.

The final answer is 6.
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Answer:

Associative property: a + (b + c), a – (b – c) ≠ (a – b) – c, a × (b × c) = (a × b) × c, and a ÷ (b ÷ c) ≠ (a ÷ b) ÷ c

When a = ½ and b = ¾

Now, for checking a × b = b × a, consider LHS and RHS.

LHS = a × b = ½ × ¾ = ⅜

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Step-by-step explanation:

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Algebraic expression for 6 notebooks at S dollars
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6=S
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if the eggs in a basket are removed 2 at a time, 1 egg will remain. if the eggs are removed 3 at a time, 2 eggs will remain. if
Yanka [14]

The least number of eggs that could be in the basket is 119.

Multiple of the number:

The multiple is the numbers you get when you multiply a certain number by an integer.

Given,

If the eggs in a basket are removed 2 at a time, 1 egg will remain.

If the eggs are removed 3 at a time, 2 eggs will remain.

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So N is 1 less than a multiple of 2, so

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=> N=3B-1

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=> N=4C-1

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=> N = 5D - 1

For 6,

=> N = 6E - 1

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So,

N => 7F

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Therefore,

N = 2A-1 = 3B-1 = 4C-1 = 5D-1 = 6E-1 = 7F

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N+1 = 2A = 3B = 4C = 5D = 6E = 7F+1

Through this,

N + 1 = 7F + 1

has to be a common multiple of 2,3,4,5,6.

So, the LCM of 2,3,4,5,6 is 60.

So N+1 is a multiple of 60 which means N is 1 less than a multiple of 60.

So we find the least multiple of 60 that is 1 more than a multiple

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The multiples are, 60, 59, ....but 59 is not a multiple of 7.

The next multiple of 60 is 120.  

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=> 119 = 17*7.

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To know more about Multiple here

brainly.com/question/5992872

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4 0
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Decide whether you would use a permutation, a combination, or neither. Next, write the solution using permutation notation or co
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Answer:

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Step-by-step explanation:

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Total no. of alphabets in CORRECT = 7

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So, Total No. of arrangements =   <u>7 !</u>

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