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2 years ago

Please help! I need to finish this before midnight!

Mathematics

1 answer:

IrinaVladis [17]2 years ago

6 0

Answer:

The awnser for that is -2, my friend

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What is the value of y in the following system? Y= 3x-5 6x + 3y= 15

nalin [4]

X = 2
y = 1

You can get this by replacing the y in the second equation with the 3x - 5 from the first. Then solve for x. Once you have that value, you can solve for y.

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3 years ago

Do the ratios 42/56 and 56/64 form a proportion? if they do explain your answer

Volgvan

Lets check...

42/56 = 56/64
cross multiply
(56)(56) = (42)(64)
3136 = 2688...(incorrect)...these are not proportional

proportions are nothing but equivalent fractions
42/56 = 3/4
56/64 = 7/8
as u can see, they are not equivalent fractions...so they are not proportional

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3 years ago

What is the solution to this equation?

sattari [20]

Answer:

Step-by-step explanation:

x - 9 = 17

x = 26

the answer is D

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3 years ago

For a 100 ponits : 13+(-19)= ANSWER:

KATRIN_1 [288]

Answer: -6

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

In order to help identify baby growth patterns that are unusual, we need to construct a confidence interval of the mean head cir

sukhopar [10]

Answer:

The 99% confidence interval estimate of the mean head circumference of all 2-month-old babies is (40.18cm, 41.02cm).

Step-by-step explanation:

Our sample size is 100.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

$df = 100-1 = 99$ .

Then, we need to subtract one by the confidence level $\alpha$ and divide by 2. So:

$\frac{1-\alpha}{2} = \frac{0.01}{2} = 0.005$

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 99 and 0.005 in the t-distribution table, we have $T = 2.626$

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

$s = \frac{1.6}{\sqrt{100}} = 0.16$

Now, we multiply T and s

$M = Ts = 2.626*0.16 = 0.42$

For the lower end of the interval, we subtract the sample mean by M. So the lower end of the interval here is

$L = 40.6 - 0.42 = 40.18$ cm

For the upper end of the interval, we add the sample mean and M. So the upper end of the interval here is

$L = 40.6 + 0.42 = 41.02$ cm

The 99% confidence interval estimate of the mean head circumference of all 2-month-old babies is (40.18cm, 41.02cm).

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3 years ago