Let events
A=Nathan has allergy
~A=Nathan does not have allergy
T=Nathan tests positive
~T=Nathan does not test positive
We are given
P(A)=0.75 [ probability that Nathan is allergic ]
P(T|A)=0.98 [probability of testing positive given Nathan is allergic to Penicillin]
We want to calculate probability that Nathan is allergic AND tests positive
P(T n A)
From definition of conditional probability,
P(T|A)=P(T n A)/P(A)
substitute known values,
0.98 = P(T n A) / 0.75
solving for P(T n A)
P(T n A) = 0.75*0.98 = 0.735
Hope this helps!!
Number of returns = 47
Number of returns that contain errors = 5
Number of returns that does not contain error = 47 - 5 = 42
P(selecting none that contains error in the unreplaced selection) = 42/47 x 41/46 x 40/45 = 68880 / 97290 = 0.708
option C is the correct answer.
Answer:
Height = 5
Step-by-step explanation:
On his first turn he moves one fifth of one hundred what is equal to twenty on second turn he moves twenty less one fourth of twenty what is equal to fifteen. In last time he moves eleven fourths of twenty what is equal to fifty five. Then 3rd turn he has moved ninety spaces
i hope this helps :)
Answer:
131.2
Step-by-step explanation:
x/55=31/14
x=31/13*55
x=131.153846154
