3 years ago

The melting point of matter is the temperature at which it changes from a:

Chemistry

1 answer:

lorasvet [3.4K]3 years ago

5 0

Answer:

$\boxed {\boxed {\sf Solid \ to \ liquid}}$

Explanation:

When heat is added to matter, the temperature rises. The average kinetic energy also increase and the matter melts.

When matter melts, it turns from a solid to a liquid. So, the melting point of matter is the temperature where it changes from the solid state of matter to the liquid state of matter.

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A curium-245 nucleus is hit with a neutron and changes as shown by the equation. Complete the equation by filling in the missing

Lera25 [3.4K]

Try this option:

$^{245}_{96}Cm+^1_0n=^{103}_{42}Mo+^{245+1-103-3*1}_{96+0-42-3*0}(X)+3^1_0n;$

$^{245}_{96}Cm+^1_0n=> ^{103}_{42}Mo+^{140}_{54}(X)+3^1_0n;$

$^{245}_{96}Cm+^1_0n=> ^{103}_{42}Mo+^{140}_{54}Xe+3^1_0n;$

Answer:

$^{140}_{54}Xe$

8 0

3 years ago

Read 2 more answers

A very acidic ph level is

algol [13]

1 ph is the highest ph level for an acid

3 0

3 years ago

This is the chemical formula for acetic acid (the chemical that gives the sharp taste to vinegar):

Anastaziya [24]

Answer:

0.017 mol

Explanation:

CH3COOH - acetic acid - we can write as C2O2H4

From formula C2O2H4 we can see that ratio C: O = 2:2 = 1:1, so number of moles C and O are the same.

So if we have 0.017 mol C, we should have 0.017 mol O.

3 0

3 years ago

During a titration, the pH of an analyte solution containing HA(aq) is 3.92 and the ratio of [A–]/[HA] is 0.41. What is the Ka o

Solnce55 [7]

Answer:

$Ka=4.71x10^{-4}$

Explanation:

Hello there!

In this case, according to the Henderson-Hasselbach equation, it is possible to write:

$pH=pKa+log(\frac{[A^-]}{[HA]} )$

Next, since we are given the pH and the [A–]/[HA] ratio, we can solve for the pKa as shown below:

$pKa=pH-log(\frac{[A^-]}{[HA]} )$

Now, we plug in the values to obtain:

$pKa=3.92-log(0.41 )\\\\pKa=3.33$

Next, Ka is:

$Ka=10^{-pKa}=10^{-3.33}\\\\Ka=4.71x10^{-4}$

Best regards!

3 0

3 years ago

Potassium chlorate (kclo3) decomposes in a reaction described by this chemical reaction: 2kclo3(s) → 2kcl(s) + 3o2(g) how does t

soldi70 [24.7K]

When the KClO3 decomposes, more oxygen is produced. I don't think I know any other possibility exists.<span />

5 0

4 years ago