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Dmitry_Shevchenko [17]
2 years ago
6

It took 55 days for a radioactivity of 1.75 x 1012 Bq to remain 0.135 Ci. What is the half-life of this radioactivity?

Chemistry
1 answer:
Sladkaya [172]2 years ago
7 0

From the calculations, we can see that the half life of the material is 11.4 days

<h3>What is radioactivity?</h3>

The term radioactivity refers to the spontaneous disintegration of a radioactive nucleus. The time taken for half of the radioactive material to remain.

Given that;

N/No = (1/2)^t/t1/2

N = amount that remained

No = amount that remained in the beginning

t = time taken

t1/2 = half life of the substance

N =Noe^-kt

4.995 ×10^9 = 1.75 x 10^12e^-55k

3.5* 10-2=e^-55k

k = ln3.5* 10-2/-55

k =0.06095

t1/2 = 0.693/0.06095

t1/2 = 11.4 days

Learn more about half life:brainly.com/question/24710827

#SPJ1

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In this case, since hydrochloric acid and barium hydroxide are in a 2:1 molar ratio, for the neutralization, the following moles equality must be obeyed:

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In such a way, in terms of molarities and volumes, we can compute the required volume of hydrochloric acid as shown below:

2*M_{HCl}V_{HCl}=M_{Ba(OH)_2}V_{Ba(OH)_2}\\\\V_{HCl}=\frac{M_{Ba(OH)_2}V_{Ba(OH)_2}}{2M_{HCl}} =\frac{0.101M*0.050L}{2*0.50M} \\\\V_{HCl}=5.05x10^{-3}L

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Answer:

Water's boiling point is higher than acetone's one due to the stronger intermolecular forces it has in liquid phase.

Explanation:

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In this case, since no options are given we can infer from the statement that due to water's higher boiling point than acetone we can conclude that when they are in liquid state, water has stronger intermolecular forces which allow its particles to be held in a stronger way in comparison to the acetone's molecules, for that reason, more energy will be required in order to separate them and promote the boiling process, which is attained via increasing the temperature. Besides, less energy will be required for the separation of the acetone's molecules in order to boil it when liquid, therefore, a lower temperature is required.

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