Answer:
C. A ball dropped from a height of 10 m will hit the ground at a higher speed than an identical ball dropped from a height of 5 m.
Explanation:
The statement of the hypothesis is that " the greater the height from which you drop a ball, the faster the ball will be traveling when it hits the ground because gravity has more time to speed it up ".
The hypothesis statement is quite explicit. We can deduce that objects at a higher height above the ground will hit the ground much more faster and harder compared to those at a shorter height.
A ball at height of 10m is expected to drop with a higher speed on the ground compared to an identical ball at a height of 5m.
If the balls are at the same height, they are expected to fall with the same speed so far they are identical. Also, a ball at a shorter height will fall at a lower speed.
I think it is an oxygen atom, I am not completely sure though.
As temperature increases, the average kinetic energy of a sample of gas molecules decreases.
Considering that CCL3F gas behave like an ideal gas then we can use the Ideal Gas Law
<span>PV = nRT, however is an approximation and not the only way to resolve this problem with the given data..So,at the end of the solution I am posting some sources for further understanding and a expanded point of view. </span>
<span>Data: P= 856torr, T = 300K, V= 1.1L, R = 62.36 L Torr / KMol </span>
<span>Solving and substituting in the Gas equation for n = PV / RT = (856)(1.1L) /( 62.36)(300) = 0.05 Mol. This RESULT is of any gas. To tie it up to our gas we need to look for its molecular weight:MW of CCL3F = 137.7 gm/mol. </span>
<span>Then : 0.05x 137.5 = 6.88gm of vapor </span>
<span>If we sustract the vapor weight from the TOTAL weight of liquid we have: 11.5gm - 6.88gm = 4.62 gm of liquid.d</span>
