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3 years ago

Which of these uses the force of gravity to make it move?

Physics

2 answers:

Naddik [55]3 years ago

3 0

Answer:

C: A snow sled going down hill

Natasha2012 [34]3 years ago

3 0

C: A snow sled going downhill

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If a 50microAmps current is flowing then how many electrons pass a point each minute to 2 sig figs? Please add an explanation as

defon

The equation you need to use is $Q=IT$ where Q is the charge in C, I is the current in Amps and T is the time in seconds.

So we have T = 60s
I = $50 \times 10^-^6$ A
let's work out Q
$Q=IT = (50\times 10^{-6}) \times 60 = 3 \times 10^-^3$ C
this is the total charge passing a point in a minute so divide by the charge of one electron ( $1.6 \times 10^{-19}$ ) to find the number of electrons passing the point in a minute which equals $1.875 \times 10^{16}$

6 0

3 years ago

Two equally charged, 2.807 g spheres are placed with 3.711 cm between their centers. When released, each begins to accelerate at

statuscvo [17]

$\begin{gathered} m=\text{ 2.807 g} \\ d=\text{ 3.711cm} \\ a=260.125\text{ m/s}^2 \\ m=\text{ mass of both the spheres} \\ d=\text{ distance between the centers of sphere.} \\ a=\text{ acceleration of spheres.} \end{gathered}$ $\begin{gathered} force\text{ due to the sphere having charge q, outside its surface is given by } \\ \vec{F}=\frac{1}{4\pi\epsilon_o}\frac{q_1q_2}{r^2}\hat{r} \\ q_1=charge\text{ on the source object.} \\ q_2=charge\text{ of the object in which we are observing the force.} \\ F=\text{ the force on the charged particle outside the sphere} \\ r=\text{ distance of the charged particle from the center of the sphere} \\ \hat{r}\text{= direction of the force acting on the charged particle} \end{gathered}$ $\begin{gathered} from\text{ Newton's second law} \\ F=ma \\ F=\text{ force acting on the particle.} \\ m=\text{ mass of the object.} \\ a=\text{ acceleration of the object.} \end{gathered}$ $\begin{gathered} from\text{ both the equation } \\ ma=\frac{1}{4\pi\epsilon_o}\frac{q_1q_{\frac{2}{}}}{r^2}\hat{r} \\ here\text{ q}_1\text{ and q}_2\text{ are the same, according to the question.} \end{gathered}$ $\begin{gathered} converting\text{ all the values in s.i. unit} \\ m=2.807*10^{-3}kg \\ d=3.711*10^{-2}m \\ according\text{ to the question q}_1=\text{ q}_2 \\ value\text{ of }\frac{1}{4\pi\epsilon_o}=9*10^9\text{ Nm}^2\text{/C}^2 \\ now\text{ put all the values in the above equation } \\ 2.807*10^{-3}kg*260.125\text{ m/s\textasciicircum2}=9*10^9Nm^2\text{/C}^2*\frac{q^2}{3.711*10^{-2}m} \\ \end{gathered}$ $\begin{gathered} by\text{ trasformation} \\ q=\sqrt{\frac{2.807*10^{-3}kg*260.125m/s^2*3.711*^10^{-2}m}{9*10^9Nm^2\text{/C}^2}} \\ by\text{ solving this we get } \\ q=17.3514*10^{-7}C \\ q=1.73514\text{ micro coulombs.} \end{gathered}$ Hence the correct answer is q= 1.73514 micro coulombs.

5 0

1 year ago

An aluminium bar 600mm long, with diameter 40mm, has a hole drilled in the center of the bar. The hole is 30mm in diameter and i

arsen [322]

Answer:

Explanation:

l = 600mm = 0.6m

d = 40mm = 0.04m

hd = 30mm = 0.03m (diameter of the hole)

hl = 100mm = 0.1m (hole length)

modulus of elasticity for the aluminium = 85GN/m2

compressive load = 180kN

6 0

3 years ago

Which of the following is an example of a chemical change?

bija089 [108]

HELLO THERE

THE ANSWER IS

D. A gas when vinegar and baking soda are mixed

EXTRA INFO: An exmaple of phyical change is sawing a piece of wood

BEST REGARDS QUEEN Z

HOPE THIS HELPS

5 0

3 years ago

Read 2 more answers

An unwary football player collides with a padded goalpost while running at a velocity of 7.50 m/s and comes to a full stop after

mr Goodwill [35]

Answer:

(a) 80.36 m/s^2

(b) 0.0933 second

Explanation:

initial velocity, u = 7.5 m/s

final velocity, v = 0 m/s

distance moved, s = 0.350 m

(a) Let a be the deceleration.

Use third equation of motion

$v^{2}=u^{2}+2\times a\times s$

$0^{2}=7.5^{2}+2\times a\times 0.350$

a = 80.36 m/s^2

Thus, the deceleration is 80.36 m/s^2.

(b) Let the time taken is t

Use first equation of motion

v = u + a t

0 = 7.5 + 80.36 x t

t = 0.0933 second

7 0

3 years ago