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masya89 [10]
4 years ago
10

Cual sera el caudal que lleva un rio cuando se desplaza a 200 litros cada 40 segundos

Physics
1 answer:
alisha [4.7K]4 years ago
4 0

Answer:

Q = 5 L/s

Explanation:

To find the flow you use the following formula (para calcular el caudal usted utiliza la siguiente formula):

Q=\frac{V}{t}

V: Volume (volumen) = 200L

t: time (tiempo) = 40 s

you replace the values of the parameters to calculate Q (usted reemplaza los valores de los parámteros V y t para calcular el caudal):

Q=\frac{200L}{40s}=5\frac{L}{s}

Hence, the flow is 5 L/s (por lo tanto, el caudal es de 5L/s)

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3 0
3 years ago
A generator uses a coil that has 100 turns and a 0.50-T magnetic field. The frequency of this generator is 60.0 Hz, and its emf
lana [24]

Answer:

38 m

Explanation:

Number of turns=N=100

Magnetic field=B=0.50 T

Frequency of the generator=f=60 Hz

Rms value of emf=E_{rms}=120 V

We have to find the length of the wire from which the coil is made.

Peak value of emf=E_0=E_{rms}\sqrt 2=120\times \sqrt 2=169.7 V

Length of wire=4\sqrt{\frac{NE_0}{2\pi fB}}

Substitute the values

Length of wire=4\times \sqrt{\frac{169.7\times 100}{0.50\times 2\pi\times 60}}

Length of wire=38 m

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6 0
3 years ago
The weight of a person is 500N and his foot imprint area is 0.5m^2.Calculate the total pressure exerted by person when he stands
Ghella [55]

Answer:

Pressure on both feet will be 500N/m^2  

Explanation:

Weight of the person F = 500 N

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Area of both the foot A=2\times 0.5=1m^2

We have to find pressure on both the feet

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So the pressure on both feet will be 500N/m^2 when person stands on both feet.

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3 years ago
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Olegator [25]

Answer:

T=26.03 N

Explanation:

Given that

Distance between poles = 12 m

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The component of tension in vertical direction will be T cosθ.

By force balancing

2 T cosθ = 40

here tan\theta =\dfrac{5}{6}

θ=39.80°

2 T cos39.8 = 40

T=26.03 N

6 0
3 years ago
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