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masya89 [10]
3 years ago
10

Cual sera el caudal que lleva un rio cuando se desplaza a 200 litros cada 40 segundos

Physics
1 answer:
alisha [4.7K]3 years ago
4 0

Answer:

Q = 5 L/s

Explanation:

To find the flow you use the following formula (para calcular el caudal usted utiliza la siguiente formula):

Q=\frac{V}{t}

V: Volume (volumen) = 200L

t: time (tiempo) = 40 s

you replace the values of the parameters to calculate Q (usted reemplaza los valores de los parámteros V y t para calcular el caudal):

Q=\frac{200L}{40s}=5\frac{L}{s}

Hence, the flow is 5 L/s (por lo tanto, el caudal es de 5L/s)

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KATRIN_1 [288]

Explanation:

Formula for maximum efficiency of a Carnot refrigerator is as follows.

      \frac{W}{Q_{H_{1}}} = \frac{T_{H_{1}} - T_{C_{1}}}{T_{H_{1}}} ..... (1)

And, formula for maximum efficiency of Carnot refrigerator is as follows.

     \frac{W}{Q_{C_{2}}} = \frac{T_{H_{2}} - T_{C_{2}}}{T_{C_{2}}} ...... (2)

Now, equating both equations (1) and (2) as follows.

 Q_{C_{2}} \frac{T_{H_{2}} - T_{C_{2}}}{T_{C_{2}}} = Q_{H_{1}} \frac{T_{H_{1}} - T_{C_{1}}}{T_{H_{1}}}        

        \gamma = \frac{Q_{C_{2}}}{Q_{H_{1}}}

                    = \frac{T_{C_{2}}}{T_{H_{1}}} (\frac{T_{H_{1}} - T_{C_{1}}}{T_{H_{2}} - T_{C_{2}}})

                    = \frac{250}{600} (\frac{(600 - 300)K}{300 K - 250 K})

                    = 2.5

Thus, we can conclude that the ratio of heat extracted by the refrigerator ("cooling load") to the heat delivered to the engine ("heating load") is 2.5.

4 0
3 years ago
Which statement is true? A Displacement can never be greater than distance. B Displacement can never be less than distance. C Di
qwelly [4]

Answer:

__________________

I think the answer is A.

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3 0
3 years ago
Dams are made wider at the bottom than at the top?
malfutka [58]
Yes dams are made wider at the bottom because the pressure of the water pressure is greater there
8 0
3 years ago
The Z0 boson, discovered in 1985, is the mediator of the weak nuclear force, and it typically decays very quickly. Its average r
Dvinal [7]

Answer:

The lifetime of the particle is  \Delta  t  =  2.6*10^{-25} \ s

Explanation:

From the question we are told that

    The average rest energy is E =  91.19 \ GeV =  91.19GeV  *    \frac{1.60 *10^{-10} J }{1GeV} = 1.46 *10^{-8}J

    The intrinsic width is  \Delta E  =2.5eV  = 2.5GeV   *  \frac{1.60 *10^{-10}J  }{1GeV}  =  4*10^{-10} J

The lifetime is mathematically represented as

     \Delta  t  =  \frac{h}{\Delta E}

Where h is the Planck's constant with a value of  1.055*10^{-34} \ J\cdot s  

substituting values

    \Delta  t  =  \frac{1.055*10^{-34}}{4 *10^{-10}}

     \Delta  t  =  2.6*10^{-25} \ s

6 0
3 years ago
Which of the following types of stars had the smallest initial mass? Blue main sequence Neutron star Red supergiant White dwarf
Nezavi [6.7K]

Answer:

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Explanation:

The Hertzsprung-Russell Diagram shows the mass of stars, the color, temperature and their  brightness.Stars that lie below the main sequence area such as the White dwarf have the smallest initial mass.A white dwarf star has a mass less than that of the Sun.

6 0
3 years ago
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