Cual sera el caudal que lleva un rio cuando se desplaza a 200 litros cada 40 segundos
1 answer:
Answer:
Q = 5 L/s
Explanation:
To find the flow you use the following formula (para calcular el caudal usted utiliza la siguiente formula):
V: Volume (volumen) = 200L
t: time (tiempo) = 40 s
you replace the values of the parameters to calculate Q (usted reemplaza los valores de los parámteros V y t para calcular el caudal):
Hence, the flow is 5 L/s (por lo tanto, el caudal es de 5L/s)
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where V is the potential difference applied on the wire, I the current and R the resistance. For the resistor in the problem we have:
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by using the following relationship:
Where A is the cross-sectional area of the wire and L its length.
We already have its length
, while we need to calculate the area A starting from the radius:
And now we can find the resistivity:
where V is the potential difference applied on the wire, I the current and R the resistance. For the resistor in the problem we have:
2) Now that we have the value of the resistance, we can find the resistivity of the wire
Where A is the cross-sectional area of the wire and L its length.
We already have its length
And now we can find the resistivity: