Explanation:
it will not change it's motion because it's force is less than the force applied
Where the air has low humidity
idk ;-; you can do it!
Answer: a. F doubled
b. F reduced by one-quarter i.e
1/4*(F)
c. 1/9*(F)
d. F increased by a factor of 4 i.e 4*F
e. F reduces 3/4*(F)
Explanation: Coulombs law states the force F of attraction/repulsion experience by two charges qA and qB is directly proportional to thier product and inversely proportional to the square of distance d between them. That is
F = k*(qA*qB)/d²
a. If qA is doubled therefore the force is doubled since they are directly proportional.
b. If qA and qB are half, that means thier new product would be qA/2)*qB/2 =qA*qB/4
Which means the product of charge is divided by 4 so the force would be divided by 4 too since they are directly proportional.
c. If d is tripped that is multiplied by 3. From the formula new d would be (3*d)²=9d² but force is inversely proportional to d² so instead of multiplying by 9 the force will be divided by 9
d. If d is cut into half that is divided by 2. The new d would be (d/2)²=d²/4. So d² is divided by 4 so the force would be multiplied by 4
e. If qA is tripled that is multiplied by 3. F would be multiplied by 3 also, if at the same time d is doubled (2*d)²= 4*d² . Force would be divided by 4 at same time. So we have,
3/4*F
Answer : Capacitors
Explanation : Capacitors are normally placed on transmission or distribution lines when to reduce inductive reactance.
This is because it enhances electromechanical and voltage stability , limit voltage dips at network nodes and reduces the power loss.
So, we can say that inductive reactance normally replace by the capacitors.
Answer:
Explanation:
Work is a force time the distance moved in the direction of that force, time is not a variable. Provided that the 50 N forces were applied in the same direction, the work done is identical. Assuming both applied force and direction of motion are horizontal W = Fd = 50(10) = 500J.
If the reason that one was slower is because the second person applied his force at an angle, let's say 60° below the horizontal, then the work done by the second person is 50cos60(10) = 250 J
Time IS a consideration for Power, the RATE of doing work. Provided the force and motion are horizontal, the first person applied twice as much Power as the second person doing an identical amount of work in half the time.
