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andrezito [222]
3 years ago
14

If a metal ball suspended by a rod is at rest, which force is responsible for balancing the force due to gravity?

Physics
2 answers:
sineoko [7]3 years ago
4 0
The normal force applied by the rod on tbe metal ball is the force balancing the force due to gravity.

The normal force is the force that keeps any object from going through another object and that is why tables and floors can keep things up.
cestrela7 [59]3 years ago
3 0
Any force coming from the surface and acting at a right angle to the surface is called the Normal Force<span>.
normal force </span><span>is responsible for balancing the force due to gravity.</span>
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A cruise ship sails due south at 2.50 m/s while a coast guard patrol boat heads 19.0° north of west at 4.80 m/s. What are the x-
Nesterboy [21]

Answer:

Explanation:

We shall represent the velocity of cruise ship and coast guard petrol boat in vector form .

velocity of cruise ship

Vcs = - 2.5 j

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velocity of the cruise ship relative to the patrol boat

= Vcs - Vpb

=  - 2.5 j - ( - 4.54 i + 1.56 j  )

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y-component of the velocity of the cruise ship relative to the patrol boat

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A player kicks a football from ground level with a velocity of 26.2m/s at an angle of 34.2° above the horizontal. How far back f
Amanda [17]

For the ball to go straight into the goal, the kicker needs to be no more than 6.54 meters away from the goal.

For the ball to arc into the goal, the kicker needs to be between 58.5 and 65.1 meters away from the goal.

<h3>Explanation</h3>

How long does it take for the ball to reach the goal?

Let the distance between the kicker and the goal be x meters.

Horizontal velocity of the ball will always be 26.2\times\cos{34.2\textdegree} until it lands if there's no air resistance.

The ball will arrive at the goal in \displaystyle \frac{x}{26.2\times\cos{34.2\textdegree}} seconds after it leaves the kicker.

What will be the height of the ball when it reaches the goal?

Consider the equation

\displaystyle h(t) = -\frac{1}{2}\cdot g\cdot t^{2} + v_{0,\;\text{vertical}} \cdot t + h_0.

For this soccer ball:

  • g = 9.81\;\text{m}\cdot\text{s}^{-2},
  • v_{0,\;\text{vertical}} = 26.2\times \sin{34.2\textdegree{}}\;\text{m}\cdot\text{s}^{-2},
  • h_0 = 0 since the player kicks the ball "from ground level."

\displaystyle t=\frac{x}{26.2\times\cos{34.2\textdegree}}

when the ball reaches the goal.

\displaystyle h= - 9.81 \times \frac{x^2}{(26.2\times\cos{34.2\textdegree})^2} + (26.2 \times \sin{34.2\textdegree})\times\frac{x}{26.2\times\cos{34.2\textdegree}} \\\phantom{h} = -\frac{9.81}{(26.2\times\cos{34.2\textdegree})^2}\cdot x^{2} + \frac{\sin{34.2\textdegree}}{\cos{34.2\textdegree}}\cdot x.

Solve this quadratic equation for x, x > 0.

  • x = 65.1 meters when h = 0 meters.
  • x = 6.54 or 58.5 meters when h = 4 meters.

In other words,

  • For the ball to go straight into the goal, the kicker needs to be no more than 6.54 meters away from the goal.
  • For the ball to arc into the goal, the kicker needs to be between 58.5 and 65.1 meters away from the goal.

3 0
3 years ago
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