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andrezito [222]
3 years ago
14

If a metal ball suspended by a rod is at rest, which force is responsible for balancing the force due to gravity?

Physics
2 answers:
sineoko [7]3 years ago
4 0
The normal force applied by the rod on tbe metal ball is the force balancing the force due to gravity.

The normal force is the force that keeps any object from going through another object and that is why tables and floors can keep things up.
cestrela7 [59]3 years ago
3 0
Any force coming from the surface and acting at a right angle to the surface is called the Normal Force<span>.
normal force </span><span>is responsible for balancing the force due to gravity.</span>
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A 1500 kg car drives around a flat 200-m-diameter circular track at 25m/s. What are the magnitude and direction of the net force
MakcuM [25]

The correct answer to the question is : 9375 N.

CALCULATION:

As per the question, the mass of the car  m = 1500 Kg.

The diametre of the circular track D = 200 m.

Hence, the radius of the circular path R = \frac{D}{2}

                                                                  = \frac{200}{2}\ m

                                                                  = 100 m.

The velocity of the truck v = 25 m/s.

When a body moves in a circular path, the body needs a centripetal force which helps the body stick to the orbit. It acts along the radius and towards the centre.

Hence, the force acting on the car is centripetal force.

The magnitude of the centripetal force is calculated as -

                              Force F = \frac{mv^2}{R}

                                            =  \frac{1500\times (25)^2}{100}\ N

                                            = 9375 N.           [ANS}        

The centripetal force is provided to the car in two ways. It is the friction which provides the necessary centripetal force. Sometimes friction is not sufficient. At that time, the road is banked to some extent which provides the necessary centripetal force.


6 0
3 years ago
Cindy runs 2 kilometers every morning. She takes 2 minutes for the first 250 meters, 4 minutes for the next 1,000 meters, 1 minu
Kobotan [32]
About 285 meters per minute
4 0
3 years ago
Read 2 more answers
please help me guys please please please please please please please please please please please please please​
seropon [69]

Answer:

1.F = 256 N

2.a = 8 m/s/s

By looking at the given information, you know force, and an acceleration. Therefore you have enough information to use the first formula.

F = ma

256 N = m * 8 m/s/s

m = 256 N/8 m/s/s

m = 32 Kg

6 0
3 years ago
WHOEVER RESPONDS TO THIS FIRST WILL GET BRAINIEST!!!!!!
postnew [5]

Answer:

alright i responded

Explanation:

you didnt say i had to answer

6 0
3 years ago
Read 2 more answers
As part of your daily workout, you lie on your back and push with your feet against a platform attached to two stiff springs arr
Natalija [7]

Answer:

a) F = 680 N, b)  W = 215 .4 J , c)  F = 1278.4 N

Explanation:

a) Hooke's law is

              F = k x

To find the displacement (x) let's use the elastic energy equation

            K_{e} = ½ k x²

             k = 2 K_{e}  / x²

             k = 2 85.0 / 0.250²

             k = 2720 N / m

We replace and look for elastic force

            F = 2720  0.250

            F = 680 N

b) The definition of work is

          W = ΔEm

          W = K_{ef} - K_{eo}

          W = ½ k ( x_{f}² - x₀²)

The final distance

         x_{f} = 0.250 +0.220

        x_{f} = 0.4750 m

We calculate the work

          W = ½ 2720 (0.47² - 0.25²)

          W = 215 .4 J

We calculate the strength

          F = k x_{f}

          F = 2720 0.470

          F = 1278.4 N

6 0
3 years ago
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