Answer:
The ball will hit the ground in 1.33 s if no one touches it. The equation has 2 real solutions.
Step-by-step explanation:
The ball will hit the ground when its height is equal to 0 meters, therefore using this value in the expression and solving for "t" will give us the correct solutions.
The ball will hit the ground in 1.33 s if no one touches it. The equation has 2 real solutions.
True, because if you add pi (3.14) to 0, you get the result 34.234, which is also the result of the formula which is used to shrink the dilation AND the pre-image.
Answer:
The pairs are (13,15) and (-15,-13).
Step-by-step explanation:
If n is an odd integer, the very next odd integer will be n+2.
n+1 is even (so we aren't using this number)
The sum of the squares of (n) and (n+2) is 394.
This means
(n)^2+(n+2)^2=394
n^2+(n+2)(n+2)=394
n^2+n^2+4n+4=394 since (a+b)(a+b)=a^2+2ab+b^2
Combine like terms:
2n^2+4n+4=394
Subtract 394 on both sides:
2n^2+4n-390=0
Divide both sides by 2:
n^2+2n-195=0
Now we need to find two numbers that multiply to be -195 and add up to be 2.
15 and -13 since 15(-13)=-195 and 15+(-13)=2
So the factored form is
(n+15)(n-13)=0
This means we have n+15=0 and n-13=0 to solve.
n+15=0
Subtract 15 on both sides:
n=-15
n-13=0
Add 13 on both sides:
n=13
So if n=13 , then n+2=15.
If n=-15, then n+2=-13.
Let's check both results
(n,n+2)=(13,15)
13^2+15^2=169+225=394. So (13,15) looks good!
(n,n+2)=(-15,-13)
(-15)^2+(-13)^2=225+169=394. So (-15,-13) looks good!
5 -> 15
6 -> 20
7 -> 25
8 -> 30
9 -> 35
10 -> 40
then in ones:
after 41 would be 42 and 43
the elapsed time would be 43 minutes :)
hope this helps :)
